In order to prove the triangle is a right angled triangle we need to prove that the slope of the lines CA and BC and AB have any negative reciprocals.Lets find the slopes .
AB=(-1,3), (1,2) slope of AB = 2-3/1-(-1)= -1/2 slope of AB is -1/2
BC = (1,2), (-3,1) slope of BC is 1-2/-3-1= -1/-4 slope of BC is 1/4
Slope of CA =(-3,1)(-1,3) slope of 3-1/-1-(-3)=-2/-2=1
Since the slopes do not have any negative reciprocals so the triangle is not a right angled triangle
Answer:
a) -12
b) 8+11x+11b-3x^2-3b^2-6xb
c)-52
Step-by-step explanation:
in a) we have to substitute the value of x with 5
in b) we substitute the value of x with (x+b) and then simplify
in c) just have to substitute x with -3
25 = hypothenuse
14 = opposite
Use SOHCAHTOA
Give O and H, you can use sin
Sin^-1 = 14/25 = 34.0557
Round to hundreds
Solution: 34.06
Divide 15 by 2, then square the amount.
(15/2)^2 = 225/4
Yes, it should be taken into account
