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3 years ago

He what is 3/10×2 5/6 what is that

1 answer:

3 0

to multiply them we need to turn 2 5/6 into an improper fraction. to do this multiply 2 by 6 to get 12, then add that to 5 to get 17. 2 5/6 = 17/6

now we can multiply them. 3/10 * 17/6 = 51/60

simplify: 17/20

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4230 estimated please ??????????????

Sladkaya [172]

Answer:4200

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Radioactive isotopes are commonly used to estimate artifact ages. Let X be the time in years for a Carbon-14 atom to decay to Ni

Alexeev081 [22]

Answer:

a) 1 / years

b) P ( 5000 < X < 6000) = 0.06222

c) 8267 years

d) T_1/2 = 5730.25 years

Step-by-step explanation:

Given:

- The decay constant λ = 1 / 8267

- X is an exponential random Variable

Find:

a. What are the units of What are the units of λ?

b. What is the probability the decay time is between 5000 and 6000 years?

c. Compute SD(X).

d. Compute the median decay time. The result is called the half-life of Carbon-14?

Solution:

- The decay constant λ means the rate at which the C-14 atoms decays into N-14 atom. The rate is expressed in units of 1 / year.

- The random variable X follows an exponential distribution which has a probability mass function and cumulative density functions as follows:

P ( X = t ) = λ*e^(-λ*t)

P ( X = t ) = e^(-t/8267) / 8267

P ( X < t ) = 1 - e^(-λ*t) = 1 - e^(-t/8267)

- The probability of the decay time between years 5000 and 6000 years is:

P ( 5000 < X < 6000) = 1 - e^(-6000/8267) - 1 + e^(-5000/8267)

P ( 5000 < X < 6000) = 0.06222

- The standard deviation of the exponential distribution is given by:

SD(X) = 1 / λ = 8267 years

- The median decay time for an exponential distribution is given by:

T_1/2 = Ln(2) / λ = Ln(2)*8267

T_1/2 = 5730.25 years

3 0

3 years ago

Read 2 more answers

I need your help to unscramble these words

Alinara [238K]

2. Terminating
3. Repeating
4. Like infactors
5. Unlike
6. Common denominator

4 0

3 years ago

PLSSSS HELP IVE TRIED EVERYTHING AHHHHHHH

stepladder [879]

Answer:

<u>Domain</u>: input values (x-values)

<u>Range</u>: output values (y-values)

<u>Increasing function</u>: the average rate of change is positive

<u>Decreasing function</u>: the average rate of change is negative

<u>Constant function</u>: y-values do not vary, regardless of x-values

<h3><u>Graph 1</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-2, 2]

Increasing function: (-2, 0)

Decreasing function: (0, 3)

<h3><u>Graph 2</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-2.5, 2]

Increasing function: (-2, -1) ∪ (1.5, 3)

Decreasing function: (-1, 1.5)

<h3><u>Graph 3</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-1, 2]

Increasing function: (-2, -1)

Constant: (-1, 1)

Decreasing function: (1, 3)

5 0

2 years ago

Determine the current through each of the LEDs in the circuits below. Which LED will be

Anika [276]

a. $I = 6. 1$ × $10^-4$ A

b. $I = 2. 6$ × $10^-3$ A

c. $I = 0. 04$ A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

$I = \frac{12}{19700}$

$I = 6. 1$ × $10^-4$ A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

$I = \frac{12}{4700}$

$I = 2. 6$ × $10^-3$ A

C. V= 12V

1/R = $\frac{1}{750} + \frac{1}{1200} + \frac{1}{950 }$ = $3. 22$ × $10^-3$

R = $\frac{1}{3. 22 * 10 ^-3}$ = 310. 56 Ω

$I = \frac{12}{310. 56}$

$I = 0. 04$ A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

brainly.com/question/14296509

#SPJ1

8 0

2 years ago