Answer:
x = 1
Step-by-step explanation:
CAN SOMEONE PLEASE HELP MEEEEEEEEEEE
1 answer:
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Answer:
The garden can not have area of 700ft^2
Step-by-step explanation:
We are given equation for area as
where
w is the width (in feet) of the garden
now, we are given area =700 ft^2
so, we can set area =700
and then we can solve for w
now, we can use quadratic formula
we can compare and find a,b, and c
a=-1 , b=50 , c=-700
now, we can plug values
We can see that values of w is not real
so, w does not exists when area =700
so, The garden can not have area of 700ft^2
This question is incomplete, the complete question is;
The owners of Spiffy Lube want to offer their customers a 10-minute guarantee on their standard oil change service. If the oil change takes longer than 10 minutes to complete, the customers is given a coupon for a free oil change at the next visit. Based on past history, the owners believe that the timer required to complete an oil change has a normal distribution with a mean of 8.6 minutes and a standard deviation of 1.2 minutes.
Suppose management could improve the process by reducing the mean time required for an oil change (but keeping the standard deviation the same). How much change in the mean service time would be required to allow for a 10-minute guarantee that gives a coupon to no more than 1 out of every 25 customers on average
Answer:
Required change in the mean service time is 7.8988
Step-by-step explanation:
Given the data in the question;
How much change in the mean service time would be required to allow for a 10-minute guarantee that gives a coupon to no more than 1 out of every 25 customers on average
let mean = μ
p( x > 10 ) ≤ (1/25)
p( x > 10 ) ≤ 0.4
p( x-μ / 1.2 > 10-μ / 1.2 ) ≤ 0.4
(10-μ / 1.2 ) ≤ 0.4
(10-μ / 1.2 ) ≥ ( 0.96 )
(10-μ / 1.2 ≥ 1.751
10-μ = ≥ 1.751 × 1.2
10-μ ≤ 2.1012
μ ≤ 10 - 2.1012
μ ≤ 7.8988
Therefore, required change in the mean service time is 7.8988