Add 1 to both sides:
In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that
Under this assumption, we square both sides and we have
The solutions to this equation are
But since we can only accept solutions greater than -1, we discard and accept
.
In fact, we have
and
which is the only solution.
Hi there!
There are 3 parts to this equation:
f(x)
f(x+1)
4f(x)
We must first determine these three parts separately.
<u>1) f(x)</u>
We're given that :
⇒ :
<u>2) f(x+1)</u>
Now, we must find f(x+1). To do so, add 1 to x in the original function :
⇒
<u>3) 4f(x)</u>
To find 4f(x), multiply the original function by 4:
:
<u>4) Put it all together</u>
Now, plug each of the three parts into the equation :
Factor the left side
Divide both sides by 3^x
Because this equation is true, is therefore true.
I hope this helps!
