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Annette [7]
3 years ago
14

Please help will brain list if correct no links please ​

Mathematics
1 answer:
Advocard [28]3 years ago
7 0

Answer:

C

Step-by-step explanation:

the angle opposite of it is 30

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STUV~CBED.<br> What is the similarity ratio of STUV to CBED?
ASHA 777 [7]

The similarity ratio of STUV to CBED is 0.5

<h3>How to determine the similarity ratio of STUV to CBED?</h3>

For the shapes to have a similarity ratio, it means that:

The shapes are similar (not necessarily congruent)

From the diagram, the following sides are corresponding sides

ST and CB

Where

ST = 2

CB = 1

The similarity ratio of STUV to CBED is calculated as:

Ratio = CB/ST

Substitute the known values in the above equation

Ratio =1/2

Evaluate

Ratio = 0.5

Hence, the similarity ratio of STUV to CBED is 0.5

Read more about similar shapes at:

brainly.com/question/14285697

#SPJ1

8 0
1 year ago
The volume of a sphere is 1928m. What is the surface area of the sphere to the nearest tenth?
jasenka [17]

Answer:

749.1m

Step-by-step explanation:

Hope this helped!

4 0
2 years ago
HOW DO YOU FIND ANGLE 1
Minchanka [31]

Answer:

If we add up all the angles of any triangle, we should get 180 degrees. Therefore, Angle C = 90 (angle A) - 45 (angle B) = 45 degrees. Since there was a ray drawn from A through C the exterior angle of angle C is angle 1.

Step-by-step explanation:

a "one angle" A degree (in full, a degree of arc, arc degree, or arcdegree), usually denoted by ° (the degree symbol), is a measurement of a plane angle in which one full rotation is 360 degrees. ... Because a full rotation equals 2π radians, one degree is equivalent to π180 radians.

7 0
3 years ago
Read 2 more answers
Round 218 to the nearest ten
g100num [7]
Rounding 218 ⇒ 220.

Hoped this helped.

~Bob Ross®
6 0
3 years ago
Read 2 more answers
A motorboat that travels with a speed of 20 km/hour in still water has traveled 20 km against the current and 180 km with the cu
Gala2k [10]
Recall your d = rt.  distance = rate * time.

let's say the speed of the current is "c".

keeping in mind that, when the boat is going against the current, the boat is not really going at 2kmh, but instead at " 20 - c ", because the current is subtracting speed from it.

Likewise when is going with the current, is going at a speed of " 20 + c ".

if the boat took say "t" hours on the way over, on the way back it took the slack from the whole 8 hours and "t", namely it took " 8 - t " hours.

\bf \begin{array}{lccclll}&#10;&\stackrel{km}{distance}&\stackrel{kmh}{rate}&\stackrel{hours}{time}\\&#10;&------&------&------\\&#10;\textit{against the current}&20&20-c&t\\&#10;\textit{with the current}&180&20+c&8-t&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;20=(20-c)(t)\implies \frac{20}{20-c}=t\\&#10;180=(20+c)(8-\stackrel{\downarrow }{t})\\&#10;--------------\\&#10;180=(20+c)\left( 8- \stackrel{\downarrow }{\frac{20}{20-c}}\right)&#10;\end{cases}&#10;\\\\\\&#10;180=(20+c)\left( \cfrac{(160-8c)-20}{20-c} \right)

\bf 180=(20+c)\left( \cfrac{140-8c}{20-c} \right)\implies 180(20-c)=(20+c)(140-8c)&#10;\\\\\\&#10;3600c-180c=2800-160c+140c-8c^2&#10;\\\\\\&#10;3600c-180c=2800-20c-8c^2&#10;\\\\\\&#10;3600c-180c-2800+20c+8c^2=0\implies 8c^2-160c+800=0&#10;\\\\\\&#10;c^2-20c+100=0\implies (c-10)(c-10)=0\implies \boxed{c=10}
8 0
3 years ago
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