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Tcecarenko [31]
3 years ago
14

How do I find out how to work out , y=mx+c ???

Mathematics
2 answers:
hjlf3 years ago
3 0
Y=mx+c isn't an equation to solve. It's the slope-intercept formula for graphing lines.
y and x are the variables, and m and c are the constants.
As an example, the line y=4x+2 looks like this:

zheka24 [161]3 years ago
3 0
-assuming you meant y=mx+b-

To find slope, you first pick 2 coordinates and plug them into y2-y1 divided by x2-x1. After that you can pick a coordinate and multiply by the slope you got and if necessary, add a certain number to get the y-coordinate. Then, plug your values into y=mx+b with m for slope and b for y-intercept. IF YOU ARE JUST GIVEN AN EQUATION, change the equation into slope intercept form and just answer for m being the slope and b being the y-intercept.
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\displaystyle \frac{x^4 + 10x^3 + 25x^2 + 3x - 24}{x^2 + 5x - 4} = x^2 + 5x - 4 + \frac{3x - 8}{x^2 + 5x - 4}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding

<u>Algebra II</u>

Polynomial Division

  • Long Division
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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

<em />\displaystyle \frac{x^4 + 10x^3 + 25x^2 + 3x - 24}{x^2 + 5x - 4}<em />

<em />

<u>Step 2: Long Division</u>

<em>See attachment.</em>

  1. Multiply quotient <em>a</em> and divisor, then subtract from dividend:                      \displaystyle x^2(x^2 + 5x - 4) = x^4 + 5x^3 - 4x^2 \leftarrow \text{red 1}
  2. Multiply quotient <em>b</em> and divisor, then subtract from new dividend:              \displaystyle 5x(x^2 + 5x - 4) = 5x^3 + 25x^2 - 20x \leftarrow \text{red 2}
  3. Multiply quotient <em>c</em> and divisor, then subtract from new dividend:              \displaystyle 4(x^2 + 5x - 4) = 4x^2 + 20x - 16 \leftarrow \text{red 3}
  4. Write remainder:                                                                                               \displaystyle \frac{r(x)}{b(x)} = \frac{3x - 8}{x^2 + 5x - 4}

<em>Please excuse the bad handwriting.</em>

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