Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
please mark me the brainiest
7and 5/8
5+2 is 7
3/8+2/8 is 5/8
7+5/8 is
7 and 5/8
Answer:
- x = 37
- DG = 22
- AG = 44
- AD = 66
Step-by-step explanation:
We presume your "centroid ratio theorem" tells you that AG = 2·DG, so ...
(x+7) = 2(x -15)
x + 7 = 2x - 30 . . . . eliminate parentheses
37 = x . . . . . . . . . . .add 30-x
Then AG = 37+7 = 44
and DG = 37-15 = 22.
Of course, AD = AG +GD = 44 +22 = 66
Answer:
you use disputation
Step-by-step explanation:
4 times 3x = 12x
4 times 6 = 24
