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3 years ago

What is the low end of the range of surface temperature for blue white stars

Physics

1 answer:

N76 [4]3 years ago

7 0

B 10,000 - 30,000 K Blue-white stars

A 7,500 - 10,000 K White stars

F 6,000 - 7,500 K Yellow-white stars

G 5,000 - 6,000 K Yellow stars (like the Sun)

The lowest temperature stars are red while the hottest stars are blue. Astronomers are able to measure the temperatures of the surfaces of stars by comparing their spectra to the spectrum of a black body.

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Protons and Electrons attract each other because they are oppositely charged. Protons are positively charged, and electrons are

sashaice [31]

Answer:

True, protons are positively charged, while electrons are negatively charged, therefore they attract each other.

Explanation:

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4 years ago

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1.In what type of wave is the vibration perpendicular to the direction of travel of the wave. ____

RoseWind [281]

1. The vibration is perpendicular to the direction of travel of transverse waves.

2. The vibration is parallel to the direction of travel of longitudinal waves.

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4. You produce a transverse wave when you move one end of a
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5. All waves have wavelengths.

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3 years ago

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DochEvi [55]

Answer:

The nephew

Explanation:

The nephew has a seeing eye dog which means the nephews tracks are the dogs tracks, and the dog tracks are not covered by anything which means the dog was last and stole the butterfly.

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3 years ago

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4 years ago

The kinetic energy of the emitted electrons is measured to be 10.75 ev. What is the first ionization energy of hg

Assoli18 [71]

Answer:

I = 1010 kJ/mol

Explanation:

In PES experiment mercury vapor is irradiated with ultraviolet light of wavelength 58.4 nm.

Energy of the incident photon

$E = \dfrac{hc}{\lambda}$

h is planks constant = 6.626 × 10⁻³⁴ J.s

c is speed of light = 3 x 10⁸ m/s

λ = wavelength

$E = \dfrac{6.626 \times 10^{-34}\times 3 \times 10^8}{58.4 \times 10^{-9}}$

E = 3.40 x 10⁻¹⁸ J

Energy in eV

$E = \dfrac{3.40 \times 10^{-18}}{1.6 \times 10^{-19}}$

E = 21.2 eV

first ionization energy of mercury is the difference in the kinetic energy of the ejected electron to the energy of the incident photon.

I = 21.2 eV - 10.75 eV

I = 10.45 eV

I = 10.45 x 1.6 x 10⁻¹⁹

I = 1.67 x 10⁻¹⁸ J

now,

I = (1.67 x 10⁻¹⁸ x 6.022 x 10²³) J/mol

I = 10.10 x 10⁵ J/mol

I = 1010 kJ/mol

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4 years ago