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sp2606 [1]
3 years ago
15

peach pie in a 9.00 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie pla

te moves through a distance of 183 in. Express the angular distance that the pie plate has moved through in revolutions, radians, and degrees. angular distance: revolutions angular distance: radians angular distance: ∘ If the pie is cut into 9 equal slices, express the angular size of one slice in radians, as a fraction of π. angular size=π×
Physics
1 answer:
zavuch27 [327]3 years ago
5 0

Explanation:

It is given that,

Diameter of the peach pie, d = 9 inches

Radius of the pie, r = 4.5 inches

The tray is rotated such that the rim of the pie plate moves through a distance of 183 inches, d = 183 inches

Let \theta is the angular distance that the pie plate has moved through.

It is given by :

\theta=\dfrac{d}{r}

\theta=\dfrac{183}{4.5}  

\theta=40.66\ radian

Since, 1 radian = 57.29 degrees

\theta=2329.64\ degrees

Since, 1 radian = 0.159155 revolution

\theta=6.47124\ revolution

Hence, this is the required solution.

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Air as an ideal gas enters a diffuser operating at steady state at 5 bar, 280 K with a velocity of 510 m/s. The exit velocity is
Nataly [62]

Answer:

Explanation:

Calculating the exit temperature for K = 1.4

The value of c_p is determined via the expression:

c_p = \frac{KR}{K_1}

where ;

R = universal gas constant = \frac{8.314 \ J}{28.97 \ kg.K}

k = constant = 1.4

c_p = \frac{1.4(\frac{8.314}{28.97} )}{1.4 -1}

c_p= 1.004 \ kJ/kg.K

The derived expression from mass and energy rate balances reduce for the isothermal process of ideal gas is :

0=(h_1-h_2)+\frac{(v_1^2-v_2^2)}{2}     ------ equation(1)

we can rewrite the above equation as :

0 = c_p(T_1-T_2)+ \frac{(v_1^2-v_2^2)}{2}

T_2 =T_1+ \frac{(v_1^2-v_2^2)}{2 c_p}

where:

T_1  = 280 K \\ \\ v_1 = 510 m/s \\ \\ v_2 = 120 m/s \\ \\c_p = 1.0004 \ kJ/kg.K

T_2= 280+\frac{((510)^2-(120)^2)}{2(1.004)} *\frac{1}{10^3}

T_2 = 402.36 \ K

Thus, the exit temperature = 402.36 K

The exit pressure is determined by using the relation:\frac{T_2}{T_1} = (\frac{P_2}{P_1})^\frac{k}{k-1}

P_2=P_1(\frac{T_2}{T_1})^\frac{k}{k-1}

P_2 = 5 (\frac{402.36}{280} )^\frac{1.4}{1.4-1}

P_2 = 17.79 \ bar

Therefore, the exit pressure is 17.79 bar

7 0
3 years ago
-A 180 kg hippo is riding a bicycle at a speed of 6.0
Vlad1618 [11]

Answer:

0.0675 seconds

Explanation:

From the question,

We apply newton's second law of motion

F = m(v-u)/t.................... Equation 1

Where F = force exert by the brake, v = final speed, u = initial speed m = mass of the bicycle, t = time.

make t the subject of the equation

t = m(v-u)/F................... Equation 2

Given: m = 180 kg, u = 6.0 m/s, v = 0 m/s (comes to stop), F = -1600 N ( agianst the dirction of motion)

Substitute these value into equation 2

t = 180(0-6.0)/-1600

t = -1080/-1600

t = 0.0675 seconds.

8 0
3 years ago
What is net force
IgorLugansk [536]
The answer is letter A
3 0
3 years ago
Aspect ratio is the ratio of images width to its height. a photograph is 17.5 cm wide by 14 cm high what is the aspect ratio in
Svet_ta [14]

Try 5:4 and see if it is correct

5 0
3 years ago
What is one property of a suspension that is different from that of a solution or a colloid?
Step2247 [10]

Answer:

A

Explanation:

If left to rest it will separate.  

3 0
2 years ago
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