The weight of a 75 kg person on Earth, which has an acceleration due to gravity of 9.8m/s², is 735N.
CALCULATE WEIGHT:
Weight is a force, hence, measured in Newton. It is a function of an object's mass in relation to gravity.
Weight of an object can be calculated using the following formula:
W = mg
Where;
- W = weight (N)
- m = mass (kg)
- g = acceleration due to gravity (m/s²)
The weight of the person in this question can be calculated as follows:
W = 75 × 9.8
W = 735N
Therefore, the weight of a 75 kg person on Earth, which has an acceleration due to gravity of 9.8m/s², is 735N.
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Answer: q2 = -0.05286
Explanation:
Given that
Charge q1 = - 0.00325C
Electric force F = 48900N
The electric field strength experienced by the charge will be force per unit charge. That is
E = F/q
Substitute F and q into the formula
E = 48900/0.00325
E = 15046153.85 N/C
The value of the repelled second charge will be achieved by using the formula
E = kq/d^2
Where the value of constant
k = 8.99×10^9Nm^2/C^2
d = 5.62m
Substitutes E, d and k into the formula
15046153.85 = 8.99×10^9q/5.62^2
15046153.85 = 284634186.5q
Make q the subject of formula
q2 = 15046153.85/ 28463416.5
q2 = 0.05286
Since they repelled each other, q2 will be negative. Therefore,
q2 = -0.05286
C real,inverted and smaller than the object
The answer to the question '<span>In a series of undisturbed rock layers where shale lies between sandstone below and limestone above, the __." would be limestone is youngest. Out of all the rock layers, the limestone is dated to be the youngest of all.</span>
Complete Question:
Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bury itself just below the surface. What would have to be the mass of this asteroid, in terms of the earth’s mass M, for the day to become 25.0% longer than it presently is as a result of the collision? Assume that the asteroid is very small compared to the earth and that the earth is uniform throughout.
Answer:
m = 0.001 M
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