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Neko [114]
2 years ago
10

Use these values to solve this problem. a = 1, b = -8 -3ab

Mathematics
1 answer:
svp [43]2 years ago
4 0

Answer:

24

Step-by-step explanation:

-3(1(-8))

1x(-8) = -8

-3 x -8 =24

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One positive number is one-fifth of another number. The difference between the two numbers is 260, find the numbers.
Tasya [4]

Answer:

x = 325 and y = 65

Step-by-step explanation:

Let the numbers be x and y.

y = \frac{1}{5} x

x - y = 260

Now substituting value of y in the second equation

x - \frac{1}{5} x = 260\\

4x = 1300

x = 325

y = 65

5 0
4 years ago
A moving sidewalk at an airport glides a rate of 1.8 feet per second. Walking on the moving sidewalk, you travel 100 feet forwar
uranmaximum [27]

Answer: The walking speed is 4.2 feet per second.

Step-by-step explanation:

If your walking speed is S, then we can use the relation:

Time = distance/speed.

in the moving sidewalk the speed is S + 1.8ft/s.

moving forward:

speed = S + 1.8ft/s

Distance = 100 feet

Time = T

T = 100ft/(S + 1.8ft/s)

moving in the opposite direction (now the velocity of the moving sidewalk must be subtracted)

speed = S - 1.8ft/s

distance = 40 feet

time = T

T = 40ft/(S - 1.8ft/s)

Then we have two equations:

T = 100ft/(S + 1.8ft/s)

T = 40ft/(S - 1.8ft/s)

We can replace T in the second equation by the expression in the first one:

100ft/(S + 1.8ft/s) =  40ft/(S - 1.8ft/s)

now we can solve it for S.

100ft*(S - 1.8ft/s) = 40ft*(S + 1.8ft/s)

100ft*S - (100ft*1.8ft/s) = 40ft*S + (40ft*1.8ft/s)

100ft*S - 40ft*S = (100ft*1.8ft/s)+ (40ft*1.8ft/s)

S*(100ft - 40ft) = S*60ft = (100ft*1.8ft/s)+ (40ft*1.8ft/s)

S = ( (100ft*1.8ft/s)+ (40ft*1.8ft/s) )/60ft = (252ft^2/s)/60ft = 4.2 ft/s

The walking speed is 4.2 feet per second.

6 0
3 years ago
Solve the following linear inequality: <br><br>3(x + 4) ≥ 5x – 123
Tpy6a [65]
3(x+4)\geq5x-123\\3\cdot x+3\cdot4\geq5x-123\\3x+12\geq5x-123\ \ \ \ /-12\\3x\geq5x-135\ \ \ \ /-5x\\-2x\geq-135\ \ \ /:(-2) < 0\ then\ "\geq"\ change\ "\leq"\\x\leq67.5\\\\x\in(-\infty;\ 67.5 >
6 0
3 years ago
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7 0
3 years ago
10x²+x-2= 1/2 (5x-2) h<br> solve for h
never [62]

Answer:

Step-by-step explanation:

10x²+x-2=1/2(5x-2)h

10x²+5x-4x-2=1/2(5x-2)h

5x(2x+1)-2(2x+1)=1/2(5x-2)h

2(2x+1)(5x-2)=(5x-2)h

h=[2(2x+1)(5x-2)]/(5x-2)

h=2(2x+1),5x-2≠0,x≠2/5

7 0
3 years ago
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