Can somebody solve this please
1 answer:
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Answer:
0.632
Step-by-step explanation:
Given that a homeowner is three times as likely to purchase additional jewelry coverage as additional electronics coverage
If probability of purchasing additional electronics coverage = p, then prob of purchasing jewelry coverage = 3p
The two events are independent hence joint probability is product of these two.
i.e. P(both) =
This is given as 0.2
the probability that a homeowner purchases exactly one coverage.
= Prob he purchases I + prob he purchases II-2(prob he purchases both)