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ladessa [460]
3 years ago
13

Pleaseee Help! It's Algebra II- Equations: Point Slope.

Mathematics
2 answers:
kenny6666 [7]3 years ago
5 0

point slope form is y-y1=m(x-x1)

from (6,1) y1 = 1 and x1 = 6

slope is given as -3

 so you should have y=1 =-3(x-6)

Mazyrski [523]3 years ago
3 0

Answer:

work is pictured and shown

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Find the measure of angle angle AEB in the figure below. Enter only the number. PLEASE HELP ASAP
Dafna1 [17]

Answer:

42°

Step-by-step explanation:

AD is a line

AEC and DEC are both 90°

AEB and CEB make up 90°

AEB+CEB=AEC substitute

AEB+48=90 Next use Subtraction property of equality

AEB=42

Hope this helps, if so please give me brainliest, it helps a lot. :)

Have a good day!

8 0
3 years ago
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Ava has two frogs. This is 1/3 the number of frogs that Heather has. How many frogs does Heather have?
lesya692 [45]

Answer:

2x3=6 and that the number of frogs heather has or you can do this Ava has 2 frogs and heather has 1/3 more then take the 2 and add it to the 1 and that makes three. then take both of the threes and add them together and you then have the same number of 6

Step-by-step explanation:


6 0
3 years ago
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The base radius of an ice cream cone is 3.5 cm and the slant height is 6.5 cm. What is the capacity of the ice cream cone and it
ella [17]
The formula of cone's capacity is V = (1 / 3) (pi x r x h)
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8 0
3 years ago
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lesya692 [45]

3(14 - 5x) = 16 - 12x

Distribute 3 throught the parentheses

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Move the variable to the left-hand side and change its sign

42 - 15x + 12x = 16

Move the constant to the right-hand side and change its sign

- 15x+12x=16 - 42

Collect like terms

- 3x =  - 26

Divide both sides of the equation by -3

\boxed{x =  \frac{26}{3} }

6 0
2 years ago
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A circle centered at (-2,3) and contains point (5,9) which represents the equation
SIZIF [17.4K]
The standard form of the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle, (x,y) is a point of the circle, and r is the length of the radius of the circle. When the equation of a circle is written, h,k, and r are numbers, while x and y are still variables. (x-2)^2 + (y-k)^2 = 16 is an example of a circle. The problem gives us two of the three things that a circle has, a point (5,9) and the center (-2,3). We need to find the radius in order to write the equation. We substitute -2 for h, 3 for k, 5 for x, and 9 for y to get (5 - (-2))^2 + (9 - 3)^2 = r^2 We simplify: 49 + 36 = r^2, r^2 = 85. We only need to know r^2 because the equation of a circle has r^2. We now have all the information to write the equation of a circle. (x + 2)^2 + (y - 3)^2 = 85.
8 0
3 years ago
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