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2 years ago

Please help me find the area of this shape

Mathematics

2 answers:

umka21 [38]2 years ago

4 0

Answer:

The area of the shaded shape is 62 m².

Step-by-step explanation:

Area of shape: (7 x 4) + (9 x 3) + (7 x 1)

=> 28 + 27 + 7
=> 62 m²

Hence, the area of the shaded shape is 62 m².

Please check the PDF file for work.

Hoped this helped.

$BrainiacUser1357$

Download pdf

natulia [17]2 years ago

3 0

Answer:

62m squared

Step-by-step explanation:

Area= Length x Width. To figure out the area of a strange shape, you should divide it into portions. The top section would be calculated as 4x7=28. The second long and skinny rectangle at the middle is 3x10 (the three being from 7-4 and the 10 from 14-10, both values being the remainder of the space without the first shape), which equals 30. The final shape is the rectangle at the bottom, and to calculate its area the equation would be 1x4=4. You add all these values together (28+30+4) to get 62 metres squared (dont forget the sqaured!).

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3 years ago

Question A: Suppose n - 15 is a whole number. What do you know

larisa [96]

Answer:

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Step-by-step explanation:

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4 years ago

Find the points of intersection of the equation: xy=2 and x+y =4

Blizzard [7]

Answer: $\Large\boxed{(2+\sqrt{2},~2-\sqrt{x} )~~and~~ (2-\sqrt{2},~2+\sqrt{x} )}$

Step-by-step explanation:

Given the system of equations

$1)~xy=2$

$2)~x+y=4$

Divide x on both sides of the 1) equation

$xy=2$

$xy\div x=2\div x$

$y=\dfrac{2}{x}$

Current system

$1)~y=\dfrac{2}{x}$

$2)~x+y=4$

Substitute the 1) equation into the 2) equation

$x+(\dfrac{2}{x} )=4$

Multiply x on both sides

$x\times x+\dfrac{2}{x}\times x=4\times x$

$x^2+2=4x$

Subtract 4x on both sides

$x^2+2-4x=4x-4x$

$x^2-4x+2=0$

Use the quadratic formula to solve for the x value

$x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(1)(2)} }{2(1)}$

$x=2\pm\sqrt{2}$

Substitute the x value into one of the equations to find the y value

$xy=2$

$(2+\sqrt{2} )y=2$

$y=2-\sqrt{2}$

$OR$

$xy=2$

$(2-\sqrt{2} )y=2$

$y=2+\sqrt{2}$

Therefore, the points of intersection are

$\Large\boxed{(2+\sqrt{2},~2-\sqrt{x} )~~and~~ (2-\sqrt{2},~2+\sqrt{x} )}$

Hope this helps!! :)

Please let me know if you have any questions

5 0

1 year ago

Read 2 more answers

The y- intercept is when x= ?

zepelin [54]

Answer:

The y-intercept is the point at which the graph crosses the y-axis. At this point, the x-coordinate is zero. To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y.

Step-by-step explanation:

hope it helps

6 0

3 years ago