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Zielflug [23.3K]
3 years ago
7

Determine the zeros of r=2sin5theta

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

\theta=\frac{n\pi}{5}

Step-by-step explanation:

You have the following function:

r=2sin5\theta          (1)

In order to find the zeros of the function you equal to zero the equation (1), and then you solve for θ:

2sin5\theta=0\\\\sin5\theta=0\\\\5\theta=sin^{-1}(0)=n\pi;\ \ \ \ n=0,1,2,3,..\\\\\theta=\frac{n\pi}{5}

Then, there are infinite zeros for the function of the equation (1), because n has infinite positive integers values.

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