Answer:
A) sin θ = 3/5
B) tan θ = 3/4
C) csc θ = 5/3
D) sec θ = 5/4
E) cot θ = 4/3
Step-by-step explanation:
We are told that cos θ = 4/5
That θ is the acute angle of a right angle triangle.
To find the remaining trigonometric functions for angle θ, we need to find the 3rd side of the triangle.
Now, the identity cos θ means adjacent/hypotenuse.
Thus, adjacent side = 4
Hypotenuse = 5
Using pythagoras theorem, we can find the third side which is called opposite;
Opposite = √(5² - 4²)
Opposite = √(25 - 16)
Opposite = √9
Opposite = 3
A) sin θ
Trigonometric ratio for sin θ is opposite/hypotenuse. Thus;
sin θ = 3/5
B) tan θ
Trigonometric ratio for tan θ is opposite/adjacent. Thus;
tan θ = 3/4
C) csc θ
Trigonometric ratio for csc θ is 1/sin θ. Thus;
csc θ = 1/(3/5)
csc θ = 5/3
D) sec θ
Trigonometric ratio for sec θ is 1/cos θ. Thus;
sec θ = 1/(4/5)
sec θ = 5/4
E) cot θ
Trigonometric ratio for cot θ is 1/tan θ. Thus;
cot θ = 1/(3/4)
cot θ = 4/3
So the angle that's next to the 62 is 118. Now that means the other angles have to add up to 62. 62-14= 48 and 48/2 is 24 so X=24. Good luck! :)
You can divide the polygon into a triangle (VMR) and rectangle(VEDR)
VE=5
VR=6
The area for VEDR would be:
area= VE*VR= 5*6= 30
triangle height=3
VR=6
The area for VMR
area= 1/2 * 3 * 6= 9
Total area= 30 + 9 = 39
Answer:
Polynomial Expression.
Step-by-step explanation:
(5/8) × 48 = (8/15) × n
Multiply by the inverse of the coefficient of n. That inverse is 15/8.
n = (15/8)×(5/8)×48 = (75/64)×48 = 225/4 = 56 1/4
5/8 of 48 is equal to 8/15 of 56 1/4
