$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ j(\stackrel{x_1}{-8}~,~\stackrel{y_1}{4})\qquad k(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x-8}{2}~~,~~\cfrac{y+4}{2} \right)~~=~~\stackrel{m}{(-3,2)}\implies \begin{cases} \cfrac{x-8}{2}=-3\\[0.8em] x-8=-6\\ \boxed{x=2}\\[-0.5em] \hrulefill\\ \cfrac{y+4}{2}=2\\[0.8em] y+4=4\\ \boxed{y=0} \end{cases}$

4 0

3 years ago

Find the equation of the line that passes through he points (2,6) and (-2,4)

stepan [7]

First Find slope by using $\frac{y2-y1}{x2-x1}$

$\frac{4-6}{-2-2} = \frac{-2}{-4} = \frac{1}{2}$

Now use point Slope form to find the equation of the line (y-y₁)=m(x-x₁)
(y-6)= $\frac{1}{2}$ (x-2)
y-6= $\frac{1}{2} x-1$
y= $\frac{1}{2} x+5$ is your equation

7 0

2 years ago

Can someone help me with these 2?

pochemuha

Answer:

so this one could be a little tricky to understand over the computer.Im going to try my best though.

Step-by-step explanation:

Its hard to explain how i got the answer.

im not going to try and do it.

7-5

8-2.5

really hope this helps. :)

7 0

3 years ago

Degree of slant; inclination​

Degree of slant; inclination