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velikii [3]
3 years ago
5

Find two consecutive even numbers such that the difference of one-half the larger and two-fifths the smaller is equal to 38

Mathematics
1 answer:
expeople1 [14]3 years ago
6 0
EXPLANATION

The consecutive even numbers are
370 \: and \: 372

EXPLANATION

Let
x
be the first even number then, the next even number will be,

x + 2

The difference of one-half the larger one and two-fifth the smaller one is 38 gives the equation,


\frac{1}{2} (x + 2) -  \frac{2}{5} x = 38


We multiply through with an LCM of 10 to get,



10 \times \frac{1}{2} (x + 2) - 10 \times  \frac{2}{5} x = 38 \times 10


This simplifies to,


5(x + 2) -  4x = 380


We expand the brackets to get,


5x + 10 - 4x = 380

We group like terms to get,


5x - 4x = 380 - 10



This simplifies to
x = 370

Therefore the next even number is is
372
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Using the normal distribution, it is found that there is a 0.1357 = 13.57% probability that the total  amount paid for these second movies will exceed $15.00.

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • For n instances of a normal variable, the mean is n\mu and the standard error is s = \sigma\sqrt{n}

In this problem:

  • Mean of $0.47, standard deviation $0.15, hence \mu = 0.47, \sigma = 0.15
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The probability is <u>1 subtracted by the p-value of Z when X = 15</u>, hence:

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1 - 0.8643 = 0.1357.

0.1357 = 13.57% probability that the total  amount paid for these second movies will exceed $15.00.

A similar problem is given at brainly.com/question/25769446

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