it would be 3 because when you add it, it gets to be 932 and the tens place is 3.
The elimination method is a sufficient way to solve problems.
2x+y= 20
6x-5y=12
Add 5y to the one equation.
2x+6y= 20
6x= 12
Subtract 2x from both sides.
6y= 20
4x= 12
Divide 6 by 20.
y= 3.3
Divide 4 by 12.
x= 3
I hope this helped you!
Brainliest answer is appreciated!
Answer:
E: L is perpendicular to a line with slope 
.
Lines are perpendicular if the negative reciprocal of the slope is equal. For example, the reciprocal of 
is 
(remember, to get the reciprocal, simply switch the numerator and the denominator).
So, the negative reciprocal of is . This represents the slope of a line that is perpendicular.
10*3=30
30*3=90
90*3=270
270*3=810
or
10*3^1=30
10*3^2=90
10*3^3=270
10*3^4=810
the next two terms of this sequence are 270 and 810.
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get
= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],
applying L'Hospital rule again ,we get,
= > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2
For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.
Hence 2a - b =0 => 2a = b ------(A)
limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,
= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2
[0/0 form], applying L'Hospital rule again ,we get,
limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2
from (A), we have , 2a = b => 2a = -2 => a = -1
Hence a =-1 & b = -2
