Ask question

Ask question

All categories

2 years ago

6

Need help asap! im on a test

1 answer:

ki77a [65]2 years ago

7 0

Answer:

answer is 5

hopefully that helped

You might be interested in

If f(x)=4x+7 and g(x)=x^3, what is (g°f)(-1)

Annette [7]

Answer:

The answer is (g°f)(-1) = 27

Step-by-step explanation:

* (g°f)(1) ⇒ means make the domain of g is the range of f

- At first find the value of f(-1)

- Take the answer and substitute it as the value of x for g

- So the range of f is the domain of g

∵ f(x) = 4x + 7

∵ The domain of f = -1 ⇒ x is the domain

∴ f(-1) = 4(-1) + 7 = -4 + 7 = 3 ⇒ f(-1) is the range

∵ g(x) = x³

∵ x = f(-1) = 3 ⇒ the domain of g

∴ g(3) = 3³ = 27 ⇒ the range of g

* (g°f)(-1) = 27

7 0

3 years ago

Approximate the area under the curve over the specified interval by using the indicated number of subintervals (or rectangles) a

RideAnS [48]

Split up [1, 3] into 4 subintervals:

[1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]

each with length (3 - 1)/2 = 1/2.

The right endpoints $r_i$ are {3/2, 2, 5/2, 3}, which we can index by the sequence

$r_i=1+\dfrac i2$

with $1\le i\le4$ .

Evaluating the function at the right endpoints gives the sampling points $f(r_i)$ , {27/4, 5, 11/4, 0}.

Then the area is approximated by

$\displaystyle\int_1^3f(x)\,\mathrm dx\approx\frac12\sum_{i=1}^4f(r_i)=\frac12\left(\frac{27}4+5+\frac{11}4+0\right)=\boxed{\frac{29}4}$

5 0

2 years ago

Which expression is equivalent to (7x - 5)-(3x - 2)?

Tcecarenko [31]

Answer:

option D

Step-by-step explanation:

(7x - 5)-(3x - 2)

7x-5-3x+2

4x-3

6 0

3 years ago

Read 2 more answers

Find X and missing angle

Ede4ka [16]

Answer:

15

Step-by-step explanation:

all triangles are 180 so 180-75-90 =15

6 0

2 years ago

Read 2 more answers

1.)Solve the inequality. Graph the solution.

Anika [276]

Answer:

Part 1) $r\geq \sqrt[3]{-6}$

Part 2) $s>4/43$

Part 3) $z\leq6$

Part 4) $t>-7$

Part 5) $q$

Part 6) $p\geq -121/13$

Step-by-step explanation:

Part 1) $-r^{3}\leq 6$

Multiply by -1 both sides

$r^{3}\geq -6$

$r\geq \sqrt[3]{-6}$

$r\geq -1.817$

The solution is the interval -------> [-1.817,∞)

The solution in the attached figure N 1

Part 2) $-4>-43s$

rewrite

$-43s$

Multiply by -1 both sides

$43s>4$

$s>4/43$

$s>0.09$

The solution is the interval--------> (0.09,∞)

The solution in the attached figure N 2

Part 3) $z-2-6\leq-2$

combine like terms

$z-8\leq-2$

Adds 8 both sides

$z\leq-2+8$

$z\leq6$

The solution is the interval--------> (-∞,6]

The solution in the attached figure N 3

Part 4) $-2t-5$

Adds 5 both sides

$-2t$

$-2t$

Multiply by -1 both sides

$2t>-14$

Divide by 2 both sides

$t>-7$

The solution is the interval--------> (-7,∞)

The solution in the attached figure N 4

Part 5) $7(q+2)$

applying distributive property left side

$7q+14$

Subtract 14 both sides

$7q$

$7q$

Divide by 7 both sides

$q$

$q$

The solution is the interval--------> (-∞,-13)

The solution in the attached figure N 5

Part 6) $-13(p+9)\leq4$

applying distributive property left side

$-13p-117\leq4$

Adds 117 both sides

$-13p\leq4+117$

$-13p\leq 121$

Divide by -1 both sides

$13p\geq -121$

Divide by 13 both sides

$p\geq -121/13$

$p\geq -9.31$

The solution is the interval--------> [-9.31,∞)

The solution in the attached figure N 5

4 0

3 years ago