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lisabon 2012 [21]
2 years ago
10

write an equation in slope intercept form for the line that passes through the point, and is perpendicular to the line y=-1/3x+9

;(-6,-2)
Mathematics
1 answer:
aleksklad [387]2 years ago
8 0

Answer:

Step-by-step explanation:

y=-1/3x+9

This is written in the format y=mx+b, where m is the slope and b the y-intercept (the value of y when x=0).

Perpendicular lines have a slope that is the negative inverse of the slope of the reference line, in this case -(1/3).  The new slope is 3.  equation is:

y = 3x + b

To find b, enter the given point, (-6,-2) and solve for b:

y = 3x + b

-2 = 3(-6) + b

-2 = -18 + b

b = 16

The full equation is y=3x + 18

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