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lisabon 2012 [21]
3 years ago
10

write an equation in slope intercept form for the line that passes through the point, and is perpendicular to the line y=-1/3x+9

;(-6,-2)
Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

Step-by-step explanation:

y=-1/3x+9

This is written in the format y=mx+b, where m is the slope and b the y-intercept (the value of y when x=0).

Perpendicular lines have a slope that is the negative inverse of the slope of the reference line, in this case -(1/3).  The new slope is 3.  equation is:

y = 3x + b

To find b, enter the given point, (-6,-2) and solve for b:

y = 3x + b

-2 = 3(-6) + b

-2 = -18 + b

b = 16

The full equation is y=3x + 18

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kodGreya [7K]

Answer:

The maximum height of the ball is: 14.0625ft

Step-by-step explanation:

The missing information is:

h(t) = 30t - 16t^2

Required

The maximum height the ball attained

First, we calculate the time to reach the maximum height.

For a function: h(t) = at^2 + bt + c

The maximum is: t = \frac{-b}{2a}

So, the maximum of h(t) = 30t - 16t^2 is:

t = \frac{-b}{2a}

Where

a = -16; b = 30

So:

t = -\frac{30}{2*-16}

t = -\frac{30}{-32}

t = \frac{30}{32}

t = 0.9375

The maximum height is then calculated as:

h(t) = 30t - 16t^2

h(0.9375) = 30 * 0.9375- 16 * 0.9375^2

h(0.9375) = 28.125- 14.0625

h(0.9375) = 14.0625

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Answer:

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