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Andru [333]
2 years ago
10

PLS HELP!! Ill mark brainliest!

Mathematics
1 answer:
Artist 52 [7]2 years ago
8 0

Answer:

120 cm^3

Step-by-step explanation:

1. 9 times 5 =45

2. 45 divided by 3 = 15

3. 15 times 8 = 120

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emmainna [20.7K]
22/2 = 11
11 x 3 = 33
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3 years ago
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M% of n? Meaning that you won't get an actual number. For example, m/100*n.
allochka39001 [22]

Answer:

\frac{m \times n}{100}

Step-by-step explanation:

The value in 100=m

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3 years ago
Find the value of the variable and DF if D is between C and F if CD 4y -9, DF 2y-7, and CF 14.
Yuri [45]
CF = CD + DF (since D is simply a point on the line, and C to that point added onto F to that point is CF), so 4y-9+2y-7=14. Adding it up, we get 6y-16=14 and adding by 16 we get 30=6y. Dividing both sides by 6, we get y=5. Plugging that into DF, we get 10-7=DF=3
4 0
3 years ago
Madisyn is planting crops in a triangular garden. She is trying to find the amount of fencing
MrRissso [65]

Answer:

Fencing needed = 20.8 units

Step-by-step explanation:

From the figure attached,

Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).

We have to find the length of fence required to cover the triangular garden.

Amount of fencing required = Perimeter of the triangular garden

Perimeter of the garden = AB + BC + AC

Formula to get the distance between A and B,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB = \sqrt{(0-6)^2+(6-5)^2} = \sqrt{37}

BC = \sqrt{(6-5)^2+(5+1)^2} = \sqrt{37}

AC = \sqrt{(0-5)^2+(6+1)^2} = \sqrt{74}

Perimeter = \sqrt{37}+\sqrt{37}+\sqrt{74}

                = 6.08 + 6.08 + 8.60

                = 20.76

                ≈ 20.8 units

Therefore, amount of fencing required to cover the triangular park is 20.8 units.

3 0
3 years ago
Evaluate the expression and select the appropriate response. 4.25 + 3.50 + 8.25
fomenos

Answer:

The answer is 16.

Step-by-step explanation:

7 0
3 years ago
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