True. The image of a translation is always congruent to the pre-image.
Proof: every point of the pre-image is move exactly the same distance and the same direction. That means that the shape stay the same but it is just located in a different place.
Hope this helps :)
Answer:
9
Step-by-step explanation:
UT^2 = UV * UW
6^2 = (x - 7)(x - 7 + 5)
36 = (x - 7)(x - 2)
36 = x^2 - 2x - 7x + 14
x^2 - 9x - 22 = 0
(x - 11)(x + 2) = 0
x - 11 = 0 or x + 2 = 0
x = 11
UW = x - 7 + 5
UW = 11 - 7 + 5
UW = 9
Answer:
Answer is 360
to find each of the angles take 360 ÷ by the number of sides , in this case is 360 ÷ 6 = 60
Answer:
E. 2, 3, 4
Step-by-step explanation:
The sum of the shortest two sides must exceed the longest side. That is only the case for the set ...
{2, 3, 4}
Assuming you mean

that means as x approaches 4
if we sub 0 for x we get
0/0
and intermitent form
use l'hopital's rule
so
take the derivitive of the top and bottom seperatly
l'hopitals rule is something like
if

results in 0/0 or -∞/∞ or∞/∞ then keep doing it until f(n)/g(n) gives a form that isn't intermitent
so
take derivitive of top and bottom

now, if we subsitute 4 for x we get

=

=

=

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