Isosceles & Equilateral Triangles solve for x & then solve for y *
1 answer:
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The range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].
<h3>What is the range of the function?</h3>Range of a function is the set of all the possible output values which are valid for that function.
The trigonometry function given in the problem is,
The above function can be written as,
The above function is the arc of sine function. The domain of arc of sine ranges from -1 to 1.
This is the domain of the inverse of sine function. In the attached image below, the graph of inverse sine function is plotted. The range of this function is,
Thus, the range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].
Learn more about the range of the function here;
Answer:
The last table given See attached image)
Step-by-step explanation:
Notice that they are asking for the inverse function to the one with the detailed relationship given. The original relationship was assigning to the Domain of number of people attending, the Range of values for charges.
Therefore, the inverse function will be assigning in the opposite way: from the average charges (now the Domain of this relationship), to the number of people attending (now the Range of this relationship). The relationship should also maintain the original element to element connection:
What was:
(20, $10) should now be ($10, 20)
(26, $6.25) should now be ($6.25, 26)
(35, $4) should now be ($4, 35)
This is exactly represented by the last table (see also image attached)
