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2 years ago

7

the height of the gem stone is 2.668 centimeters. the volume of the gem stone is 7.4793cubic centimeters. what is the side lengh

t of the base of the gem stone

1 answer:

Solnce55 [7]2 years ago

7 0

Answer:

i looked it up on google because i coul =d not figure it out and it says it is unkwon.

Step-by-step explanation:

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The measure I NEED HELP NOW!!!!!!!

Goshia [24]

Answer:

what is the question??

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I need help solving this

Stolb23 [73]

Step-by-step explanation:

So in the equation given, y = 2x - 3

you substitute x for whats given in the table in the x column.

Example

In the graph the first number under the x colum is -1.

y = 2x - 3 in the equation you take out x and put -1.

So now the equation becomes y = 2 × -1 - 3.

Using bedmas to solve the question you should get -5

Which now means y = -5

To plot the point now x would be -1 and y would be -5 (-1, -5)

Same thing for the second number in the x Column.

y = 2 × 1 - 3 which equals -1

To plot it

x = 1 y = -1. (1, -1)

And for the last number 3.

Agai. You substitute x for 3 which makes the equation y = 2 × 3 - 3

this gives you 3 and to plot it

x would be 3 and y would be 3

4 0

2 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

Find m<_6 if m<_8=120 degrees (show work if possible).

shepuryov [24]

Answer:

h

Step-by-step explanation:

i h you h we all h ya know

3 0

3 years ago

Simplify 7 (2x + 4) + 14.

bearhunter [10]

Answer: 14x + 42

7(2x+4)+14

14x + 28 + 14

<u>14x + 42</u>

Step-by-step explanation:

6 0

3 years ago