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AVprozaik [17]
2 years ago
7

Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.

Mathematics
1 answer:
Alexandra [31]2 years ago
7 0
37x + 45y = 7940
75x + 45y = 10,410

Since 45y is in both equations we can more easily transfer from first equation to 2nd equation.

In the first equation, subtract 37x from each side and you have 45y = 7940 - 37x. Replace the 45y in the second equation with (7940 - 37x).

Now you have 75x + (7940 - 37x) = 10,410

Simplify by combining 75x - 37x and you have 38x + 7940 = 10,410

Subtract 7940 from both sides and you have 38x = 2470.

Divide both sides by 38 and you have x = 65

To solve for y, take you first equation (or even the second one) and substitute c for 65.

(37 x 65) + 45y = 7940
2405 + 45y = 7940

Subtract 2405 from each side.

45y = 5535

Divide each side by 45 and you have y = 123

Regular tickets = $65
VIP tickets = $123
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Can you help me graph and list the (Zeros, Maximums, Minimums, Asymptotes)
Marina86 [1]

The zero of the function is at 33.69 degree , the graph is plotted and attached with the answer.

<h3>What is a Function ?</h3>

A function is a law that relates a dependent variable and an independent variable with each other

It is given that

y = 2tan (x - π/2) +3

To find the zeroes of a function that function has to be equated to zero.

2tan (x - π/2) +3 = 0

2tan (x - π/2)  = -3

tan (x - π/2)  = -3/2

x - 90 = -56.31

x = 33.69 degree

The zero of the function is at 33.69 degree

For finding the maxima /minima

the derivative is

dy/dx = 2 sec² (x - π/2)

the point at which the slope is zero is substituted in the second derivative to find maxima/minima

d²y/dx² = 4 sec² (x - π/2) tan (x - π/2)

if the value is negative then it is a maxima and if it is positive it is a minima.

The vertical asymptote is found by finding the values that make the function undefined

x = 0+ πn

No horizontal or oblique asymptote

To know more about Function

brainly.com/question/12431044

#SPJ1

5 0
2 years ago
Round the following percentages to one decimal place.0.698%53.123%0.075%34.337%3.876%
balandron [24]

To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}

4 0
2 years ago
I've been stuck on this for an hour. Can someone help?
kicyunya [14]
I cant read the price numbers which price numbers are there left
4 0
4 years ago
JoAnn works in a publicity office at the state university. She is paid
sleet_krkn [62]
JoAnn works 43 hrs week.
3 0
3 years ago
Read 2 more answers
Find the mean and median of these data: 2, 5, 9, 11, 17, 19.
Harrizon [31]
<span>data: 2, 5, 9, 11, 17, 19
</span>
median is the middle number
median = (9+11)/2 = 10

mean = average
mean = (2 + 5 + 9 + 11+  17 + 19)/6
mean = 63/6
mean = 10.5
6 0
3 years ago
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