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zavuch27 [327]
3 years ago
5

If Two-thirds = StartFraction x over 12 EndFraction, what is the value of x? 4 8 18 24

Mathematics
2 answers:
Inessa [10]3 years ago
6 0

Answer:

8

Step-by-step explanation:

\frac{2}{3}  =  \frac{x}{12}  \\ x =  \frac{2 \times 12}{3}  \\ x = 2 \times 4 \\ x = 8

svlad2 [7]3 years ago
5 0

Answer:

B) 8

Step-by-step explanation:

<h2>2\3= X/12</h2><h2>3X=24</h2><h2>24÷3=8</h2><h2>The answer is 8 </h2>
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Find the Center and the radius of the circle<br> x2 + y2 - 6x + 8y- 7 = 0.
777dan777 [17]

Answer:

C(3,-4), r=4*sqrt(2)

Step-by-step explanation:

C(p, q)

x^2+y^2+dx+ey+f=0

p=-d/2, q=-e/2, r^2=p^2+q^2-f

x^2+y^2 - 6x+8y-7=0

p=-(-6)/2=6/2=3

q=-8/2=-4

r^2=3^2 +(-4)^2+7

r^2=9+16+7

r^2=32

r=sqrt(32)

r=sqrt(16*2)

r=4*sqrt(2)

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3 years ago
Could you help me with this. <br><br> Express in simplest radical form.<br> 162<br><br> ​
Ivanshal [37]

Answer:

The square root of 162 in its simplest form means to get the number 162 inside the radical √ as low as possible.

Here is how to do that! First we write the square root of 162 like this:

√162

The largest perfect square of the factors of 162 is 81. We can therefore convert √162 like this:

√81 × 2

Next, we separate the numbers inside the √ as such:

√81 × √2

√81 is a perfect square that equals 9. We can therefore put 9 outside the radical and get the final answer to square root of 162 in simplest radical form as follows:

9√2

Step-by-step explanation:

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Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert
Setler [38]

Answer:

P(x \ge 5) = 1.000 ---- At least 5 from marketing departments are extroverts

P(x=15) = 0.013 ---- All from marketing departments are extroverts

P(x = 0) = 0.002 ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

(a):\ P(x \ge 5)

n = 15 --- marketing personnel

p = 75\% --- proportion that are extroverts

Using the complement rule, we have:

P(x \ge 5) = 1 - P(x < 5)

So, we have:

P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)

P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}

P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}

P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}

P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153

P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103

So, we have:

P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103

P(x < 5) = 0.00011922283

Recall that:

P(x \ge 5) = 1 - P(x < 5)

P(x \ge 5) = 1 - 0.00011922283

P(x \ge 5) = 0.9998

P(x \ge 5) = 1.000 --- approximated

(b)\ P(x = 15)

n = 15 --- marketing personnel

p = 75\% --- proportion that are extroverts

So, we have:

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}

P(x=15) = 1 * 0.75^{15} * (0.25)^{0

P(x=15) = 0.013

(c)\ P(x = 0)

n=5 ---------- computer programmers

p = 70\% --- proportion that are introverts

So, we have:

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}

P(x = 0) = 1 * 1 * (0.30)^5

P(x = 0) = 0.002

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