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2 years ago

PLEASE HELP ME!

Mathematics

1 answer:

marshall27 [118]2 years ago

4 0

---------------------

given:

= cost of Brazilian coffee in mixture

= cost of Venezuelan coffee in mixture

= cost of mixture

---------------------

Now I can rite these equations:

(1)

(2)

Multiply both sides of (2) by and

subtract from (1)

(1)

(2)

and, since

288 kg of Brazilian coffee and 96 kg of Venezuelan coffee are needed

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What is 5 ÷ 1/5 I really need help with dividing whole numbers by fractions

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Step-by-step explanation:

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2 years ago

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According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?

scoundrel [369]

we have

$f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3$

we know that

The Rational Root Theorem states that when a root 'x' is written as a fraction in lowest terms

$x=\frac{p}{q}$

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the constant term is equal to $3$

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possible values of q are $1, 3, 5, and\ 15$

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the answer is

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I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.

elena-14-01-66 [18.8K]

Hello,

$m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\$

$cos(30^o)=\dfrac{\sqrt{3} }{2} \\$

In the triangle ABC,

$cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\$

$sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}$

In the triangle ACB,

$cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\$

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