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2 years ago

If the nth term of a number sequence is n’ – 3, find the first 3 terms and the 10th term.

Mathematics

1 answer:

Diano4ka-milaya [45]2 years ago

5 0

Answer:

First 3 terms: -2, -1, 0

10th term: 7

Step-by-step explanation:

n = 1,

n - 3 = 1 - 3 = -2

n = 2,

n - 3 = 2 - 3 = -1

n = 3,

n - 3 = 3 - 3 = 0

n = 10,

n - 3 = 10 - 3 = 7

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4 x (5+5) I need the distributive property and the answer please I need it ASAP!

Paraphin [41]

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3 years ago

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

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2 years ago

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STatiana [176]

Answer:

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2 years ago

What is the closest side lenght of this square? Area=99 square units

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Answer:

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