Answer:
0.54454
104.00902 N
Explanation:
m = Mass of wheel = 100 kg
r = Radius = 0.52 m
t = Time taken = 6 seconds
= Final angular velocity
= Initial angular velocity
= Angular acceleration
Mass of inertia is given by
![I=\dfrac{mr^2}{2}\\\Rightarrow I=\dfrac{100\times 0.52^2}{2}\\\Rightarrow I=13.52\ kgm^2](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7Bmr%5E2%7D%7B2%7D%5C%5C%5CRightarrow%20I%3D%5Cdfrac%7B100%5Ctimes%200.52%5E2%7D%7B2%7D%5C%5C%5CRightarrow%20I%3D13.52%5C%20kgm%5E2)
Angular acceleration is given by
![\alpha=\dfrac{\tau}{I}\\\Rightarrow \alpha=\dfrac{\mu fr}{I}\\\Rightarrow \alpha=\dfrac{\mu 50\times 0.52}{13.52}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B%5Ctau%7D%7BI%7D%5C%5C%5CRightarrow%20%5Calpha%3D%5Cdfrac%7B%5Cmu%20fr%7D%7BI%7D%5C%5C%5CRightarrow%20%5Calpha%3D%5Cdfrac%7B%5Cmu%2050%5Ctimes%200.52%7D%7B13.52%7D)
Equation of rotational motion
![\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=\omega_i+\dfrac{\mu (-50)\times 0.52}{13.52}t\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{\mu (-50)\times 0.52}{13.52}\times 6\\\Rightarrow 0=6.28318-11.53846\mu\\\Rightarrow \mu=\dfrac{6.28318}{11.53846}\\\Rightarrow \mu=0.54454](https://tex.z-dn.net/?f=%5Comega_f%3D%5Comega_i%2B%5Calpha%20t%5C%5C%5CRightarrow%20%5Comega_f%3D%5Comega_i%2B%5Cdfrac%7B%5Cmu%20%28-50%29%5Ctimes%200.52%7D%7B13.52%7Dt%5C%5C%5CRightarrow%200%3D60%5Ctimes%20%5Cdfrac%7B2%5Cpi%7D%7B60%7D%2B%5Cdfrac%7B%5Cmu%20%28-50%29%5Ctimes%200.52%7D%7B13.52%7D%5Ctimes%206%5C%5C%5CRightarrow%200%3D6.28318-11.53846%5Cmu%5C%5C%5CRightarrow%20%5Cmu%3D%5Cdfrac%7B6.28318%7D%7B11.53846%7D%5C%5C%5CRightarrow%20%5Cmu%3D0.54454)
The coefficient of friction is 0.54454
At r = 0.25 m
![\omega_f=\omega_i+\dfrac{0.54454 (-50)\times 0.52}{13.52}6\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{0.54454 f\times 0.25}{13.52}6\\\Rightarrow 2\pi=0.06041f\\\Rightarrow f=\dfrac{2\pi}{0.06041}\\\Rightarrow f=104.00902\ N](https://tex.z-dn.net/?f=%5Comega_f%3D%5Comega_i%2B%5Cdfrac%7B0.54454%20%28-50%29%5Ctimes%200.52%7D%7B13.52%7D6%5C%5C%5CRightarrow%200%3D60%5Ctimes%20%5Cdfrac%7B2%5Cpi%7D%7B60%7D%2B%5Cdfrac%7B0.54454%20f%5Ctimes%200.25%7D%7B13.52%7D6%5C%5C%5CRightarrow%202%5Cpi%3D0.06041f%5C%5C%5CRightarrow%20f%3D%5Cdfrac%7B2%5Cpi%7D%7B0.06041%7D%5C%5C%5CRightarrow%20f%3D104.00902%5C%20N)
The force needed to stop the wheel is 104.00902 N
It would be 78 becuase the 2 percent of 64 is many of energy lost
Answer:
You need to give the options but the formula is p=mv
Explanation:
Answer: 1.2m/s^2
Explanation: the force exerted on the car is 900N upwards
The mass of the car is 750kg
According to Newton's third law acceleration is proportional to force
F = ma
900 = 750a
a = 900/750
a = 1.2m/s^2
Answer:
the glove could be heavy so slowing down his power
Explanation:
JUST GUESSED