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xeze [42]
2 years ago
8

What do you think I should do to find the y value?

Mathematics
1 answer:
iogann1982 [59]2 years ago
3 0

Answer:

OK so finding the y value is real easy this is the equstion to find it m = [y1 - y2] / [x1 - x2] If you know x, you can solve for y to find the y value for the slope of the line. I hope this helped

~Cornasha_Weeb

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I neeeeed help with this one
skad [1K]

Answer:

All the terms are alike.

Step-by-step explanation:

6 0
4 years ago
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5/6x - 4 = 11 what does x equal?
dezoksy [38]

Answer:

18

Step-by-step explanation:

(5/6)x – 4 = 11

(5/6)x = 11 + 4

(5/6)x = 15

5x = 15×6 = 90

x = 90/5 = 18

7 0
3 years ago
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Line that would pass through both 8,5 and 9,-1
Elenna [48]

Answer:

what is the question

Step-by-step explanation:

3 0
3 years ago
Consider a circle whose equation is x + y - 2x - 8=0. Which statements are true? Select three options
Mandarinka [93]

Answer:

The standard form of the equation is

{(x   -  1)}^{2}  +  {(y - 0)}^{2} =  {3}^{2}

Step-by-step explanation:

The given circle has equation:

{x}^{2}  +  {y}^{2}  - 2x - 8 = 0

We regroup similar terms to obtain:

{x}^{2} -2x +  {y}^{2}  = 8

We now complete the square to obtain:

{x}^{2} -2x +  {( - 1)}^{2} +  {y}^{2}  = 8 +  {( - 1)}^{2}

{(x   -  1)}^{2}  +  {(y - 0)}^{2} = 9

Or

{(x - 1)}^{2}  +  {(y - 0)}^{2} =  {3}^{2}

This is now of the form:

{(x   -  h)}^{2}  +  {(y - k)}^{2} =  {r}^{2}

which is referred to as the standard form equation of the circle:

4 0
4 years ago
How do I do number 5?
rewona [7]
H(t)=-16t^2+15t+12
(e)
maximum height is reached when h'(t)=-32t+15=0, or tm=15/32 seconds.
maximum height reached = h(tm)=h(15/32)=-16(15/32)^2+15(15/32)+12
=993/64 ft
=15.516 ft.
(f) when Greg reaches water, h(t)=0=-16t^2+15t+12
Solve for t using quadratic formula,
t=[-15+/- sqrt(15^2+4*12*16)]/(2*-16)
=-0.516s or 1.4535s.
Reject negative root so
Greg reaches water at t=1.4535 seconds.
3 0
3 years ago
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