What is the ratio of 33/36

2 answers:

6 0

All you have to do is find a number that both of them is divisible by and divide it by them. for example, when you divide it by 3, you will get 11/12

nydimaria [60]3 years ago

6 0

11/12 Divide both by 3.

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$1675 at 4.6% for 4 years

zzz [600]

$1675 at 4.6% for 4 years
Interst of P = $1675 at R = 4.6% for T = 4 years = P x R x T = $1675 x 4.6% x 4 = $308.20

Hope this helps:D

5 0

3 years ago

Need ASAP! six less than twice a number is half the number plus twelve

kolezko [41]

I’m sorry but i don’t know what ur saying

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3 years ago

Don’t understand these problems...need help

hichkok12 [17]

Divide one at a time. 20x³÷5x³ = 4x³ and 30 $x^{9}$ ÷5x³ = 6x³ so the final answer is D) 4x³ + 6x³

7 0

3 years ago

Explain how to find 40x80 using mental math

nadya68 [22]

so 40 * 80 = 3,200

4 * 8 = 32

Then add the two 0's to the end

so 3,200

5 0

3 years ago

Read 2 more answers

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erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

8 0

3 years ago