6. What is the equation of a line with a slope of -4 that passes through the point (2, -1)

Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region

yanalaym [24]

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

Concepts:

Area of Square = s²

s = side

Area of Triangle = bh/2

b = base
h = height

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

Question # 16

Step One: Find the total area of two squares

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

Step Two: Find the area of the blank triangle

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

Step Three: Subtract the area of the blank triangle from the total area

Total area = 29

Area of Square = 7

29 - 7 = 22

-----------------------------------------------------------

Question # 17

Step One: Find the length of PT

Given:

PR = 4 cm
RT = 6 cm

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

Step Two: Find the length of S to PT perpendicularly

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Three: Find the area of ΔPST

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Four: Find the length of Q to PT perpendicularly

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Five: Find the area of ΔPQT

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Six: Combine area of two triangles to find the total area

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

6 0

3 years ago

Please help I don’t understand.... I will give brainliest to first and I will thank you!

Stolb23 [73]

To find the answer we can break the figure into two parts: a rectangle and a semi circle.

The perimeter of the rectangle:

(10+4)×2

=28 ft

The perimeter of the semi circle:

perimeter of a circle: 2×兀×radius

(The radius: 4/2)

We divide the perimeter by two as it is a semi circle,which is half the circumferece perimeter of a circle.

[2(3.14)(4/2)] / 2

=6.28 ft

We can then add up the numbers to find the answer, and remember that 4 cm is overlapped:

28+6.28-4

=30.28ft

Therefore the answer is 30.28ft.

Hope it helps!

5 0

3 years ago

Quality control finds on average that 0.026% of the items from a certain factory are detective. One month, 4000 items are checke

telo118 [61]

Given that 4000 items are checked in one month, let the number of detective items be represented as y.

Quality control finds on average that 0.026% of the items in the factory are detective. This implies that

$\text{Number of }\det ective\text{ items = }\frac{\text{0.026}}{100}\times\text{Total number of items checked}$

When 4000 items are checked, we have the number of detective items to be evaluated as

$\begin{gathered} \text{Number of }\det ective\text{ items = }\frac{\text{0.026}}{100}\times\text{Total number of items checked} \\ y=\frac{0.026}{100}\times4000 \\ \Rightarrow y=1.04 \end{gathered}$

Hence, the number of detective items is 1.04.

7 0

1 year ago

Can someone help me with one more pls I’ll comment on yours

just olya [345]

Answer:

A:

The perimeter of the parking lot is 302 yards.

The area of the parking lot is 5,544 yards squared.

B: Perimeter

C: Area

Step-by-step explanation:

A:

To find the perimeter of the parking lot, we add all the sides up. 2L + 2W = Perimeter.

2(63) + 2 (88) = 302

To find the area, we multiply the length by the width. 63 × 88 = 5,544.

B: We need to know the amount of chain needed to surround the parking lot. In other words, we need to line the perimeter with a chain.

C: We would be paving the entire area of the parking lot.

Hope this helps,

❤Nicki❤

6 0

4 years ago

(-1)3 exponet is 3 help me please i dont want to fail

Natali5045456 [20]

Answer:

-1

i do not remember how to solve this but i just answered a question that had this problem in it on my algebra test and that is the right answer

8 0

3 years ago