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3 years ago

10

At a sale, dresses were sold for $21 each. If the dresses originally cost $60 each, what percentage of its original price was a

dress sold for?

1 answer:

svp [43]3 years ago

8 0

Answer:

35%

Step-by-step explanation:

each = $21

cost price = $60

percentage = ?

21/60 x 100/1. To get the percentage, we divide through to get our answer

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Its 4-6=2 its easy because just keep useing numbers until the become two

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Find the probability of the following events , when a dice is thrown once:

Fudgin [204]

Answer:

Step-by-step explanation:

s a die is rolled once, therefore there are six possible outcomes, i.e., 1,2,3,4,5,6.

(a) Let A be an event ''getting a prime number''.

Favourable cases for a prime number are 2,3,5,

i.e., n(A)=3

Hence P(A)=n(A)n(S)=36=12

(b) Let A be an event ''getting a number between 3 and 6''.

Favourable cases for events A are 4 or 5.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(c) Let A be an event ''a number greater than 4''.

Favourable cases of events A are 5, 6.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(d) Let A be the event of getting a number at most 4.

∴ A={1,2,3} ⇒ n(A)=4,n(S)=6

∴ Required probability =n(A)n(S)=42=23

(e) Let A be the event of getting a factor of 6.

∴ A={1,2,36} ⇒ n(A)=4,n(A)=6

∴ Required probability =46=23

(ii) Since, a pair of dice is thrown once, so there are 36 possible outcomes. i.e.,

(a) Let A be an event ''a total 6''. Favourable cases for a total of 6 are (2,4), (4,2), (3,3), (5,1), (1,5).

i.e., n(A)=5

Hence P(A)=n(A)n(S)=536

(b) Let A be an event ''a total of 10n. Favourable cases for total of 10 are (6,4), (4,6), (5,5).

i.e., n(A)=5

P(A)=n(A)n(S)=336=112

(c) Let A be an event ''the same number of the both the dice''. Favourable cases for same number on both dice are (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).

i.e., n(A)=6

P(A)=n(A)n(S)=636=16

(d) Let A be an event ''of getting a total of 9''. Favourable cases for a total of 9 are (3,6), (6,3), (4,5), (5,4).

i.e., n(A)=4

P(A)=n(A)n(S)=436=19

(iii) We have, n(S) = 36

(a) Let A be an event ''a sum less than 7'' i.e., 2,3,4,5,6.

Favourable cases for a sum less than 7 ar

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How can you graph m(x)=5x and then compare it to f(x)=x?

erastovalidia [21]

Graph the line y=5x. Then graph the line y=x. Then look at them and describe in what ways they are the same or different.

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Engineers want to design passenger seats in commercial aircraft so that they are wide enough to fit 95 percent of adult men. Ass

zimovet [89]

Answer:

$z=1.64$

And if we solve for a we got

$a=14.4 +1.64*1.1=16.204$

The 95th percentile of the hip breadth of adult men is 16.2 inches.

Step-by-step explanation:

Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.4,1.1)$

Where $\mu=14.4$ and $\sigma=1.1$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.05$ (a)

$P(X$ (b)

We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64

Using this value we can set up the following equation:

$P(X$

$P(z$

And we have:

$z=1.64$

And if we solve for a we got

$a=14.4 +1.64*1.1=16.204$

The 95th percentile of the hip breadth of adult men is 16.2 inches.

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X is 50

Step-by-step explanation:

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