Answer:
Perimeter of Δ XYZ = 24.13
Step-by-step explanation:
In Δ XYZ is a right triangle because the XYZL is a square. Therefore the hypotenuse = 10; Looking at the 43° angle, XY is the side that is opposite the 43° angle and the YZ is the side that is adjacent to the 43°.
Using the trig ratios:
XY = opposite/ hypotenuse which is Sin 43°
Sin 43° = XY/ 10
10(Sin 43°) = XY
6.82 = XY
YZ = adjacent/hypotenuse which is Cos 43°
Cos 43° = YZ/10
10(cos 43°) = YZ
7.31 = YZ
Now the Perimeter = XY + YZ + XZ
Perimeter = 6.82 + 7.31 + 10
Perimeter = 24.13
Option A:
Midpoint of LN = (2, 3)
Solution:
In the given graph we can find the coordinates of L and N.
Coordinates of L = (–2, 3)
Coordinates of N = (6, 3)
Here, 
Let us find the midpoint of the segment LN.
<u>Midpoint formula:</u>


Midpoint of LN = (2, 3)
Option A is the correct answer.
Hence the coordinates of the midpoint of the line segment LN is (2, 3).
Answer:

Step-by-step explanation:
Solve for the value of
:

-Take
and subtract it from
:


-Add
to both sides:


So, the value of
is
.
192. You multiply each answer with four, so it's 48x4=192. Hope this helps!
Answer:
2tk^3
Step-by-step explanation: