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shutvik [7]
2 years ago
9

…………………………………………………………………

Mathematics
1 answer:
horrorfan [7]2 years ago
7 0

do you sell genius brain

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A hiker walks at a speed of 3 2/5 km per hour. How many km will the hiker walk in 40 min?
ohaa [14]

Answer:

2 4/15 km

Step-by-step explanation:

We know from the above question that:

A hiker walks at a speed of 3 2/5 km per hour.

Step 1

Convert 40 minutes to hour

60 minutes = 1 hour

40 minutes = x

Cross Multiply

60x = 40

x = 40/60

x = 2/3hr

Step 2

How many km will the hiker walk in 40 min?

The above question can be calculated as:

1 hour = 3 2/5km

2/3 hour = x km

Cross Multiply

1 × x km = 2/3 × 3 2/5 km

x km = 2/3 × 17/5 km

x km = 34/15 km

x km = 2 4/15 km

Hence the hiker would walk 2 4/15 km in 4 minutes

8 0
3 years ago
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Yuliya22 [10]

Answer:

THATS FRIKIN HARD that makes me wanna go ???????????????????????????????????????????????????????????????????????????????????????

Step-by-step explanation:

7 0
3 years ago
Explain the difference between "b divided by 10" and "b divided into 10"
blagie [28]
B divided by ten means to divide whatever b equals by ten, b divided int ten means dividing whatever b equal into ten groups. THEY MEAN THE SAME THING!!
3 0
3 years ago
A 0.30 kg bird flies in a horizontal curve of radius 20 m at 15 m/s. The force exerted by the air on the bird is about
monitta

Answer:

<h2>b)  3.48 N approx.</h2>

Step-by-step explanation:

<em>The bird will experience a centripetal force, this is the force exerted on a body that moves through a curve path.</em>

F_c = \frac{mv^2}{r}

Fc=centripetal force

m=mass

v=velocity

r=radius

Step one:

given data

mass of bird m=0.3kg

the radius of curve r= 20m

velocity v= 15 m/s

Substituting we have

F_c = \frac{0.3*15^2}{20}\\\\F_c= \frac{0.3*225}{20}\\\\ F_c=\frac{67.5}{20}\\\\F_c=3.37N

<u>The force is 3.37N</u>

7 0
3 years ago
A box contains 8 red balls, 5 brown balls, 4 purple balls, and 3 green balls. what is the probability that a purple ball will be
Tems11 [23]
The probability is 20%
3 0
3 years ago
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