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2 years ago

ABCD is a parallelogram the ratio of angle A and Angle B of this Parallelogram is 5 ratio 4 find the measure of Angle B.

Mathematics

1 answer:

sergij07 [2.7K]2 years ago

7 0

Answer:

Mhm lemme see bou this one

Step-by-step explanation:

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Simplify it plzzzzz and thx

frozen [14]

Answer:

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Step-by-step explanation:

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2 years ago

What point would be reflected across the y-axis to ( − 3, − 9) ?

Aloiza [94]

Answer:

(-3, 9)

Step-by-step explanation:

If a point was reflected across the y-axis, then the y-coordinate would change signs (from negative to positive or from positive to negative). Using this, we could find the original point by changing the sign of the y-coordinate. As you may already see, this is really just reflecting the point across the y-axis again. By doing this, you get the point (-3, 9).

The point would be (-3, 9).

I hope this helps. :)

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2 years ago

A density graph for all of the possible times from 50 seconds to 300 seconds can be used to find which of the foll

Anarel [89]

Answer:

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Step-by-step explanation:

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2 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

2 years ago

A cylinder has a volume of 360 cubic centimeters. Find the volume of a cone with the same height and diameter as

harina [27]

Formula for the cylinder = V=πr2h

Formula for the cone = 1/3πr²H

Description:

So if the cone and a cylinder have the same radius and the same height then it will be greater. So plug in these formula.

Formula:

Vcone = 3Vcone

Vcylinder = 360cm³

Vcone = 1/3 360cm³ = 120cm³

Answer: 120cm³

Hope this helps.

4 0

2 years ago

ABCD is a parallelogram the ratio of angle A and Angle B of this Parallelogram is 5 ratio 4 find the measure of Angle B.​

ABCD is a parallelogram the ratio of angle A and Angle B of this Parallelogram is 5 ratio 4 find the measure of Angle B.