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Shtirlitz [24]
3 years ago
6

How how how how howHello Americans greetings from the Philippines ​

Chemistry
2 answers:
Studentka2010 [4]3 years ago
4 0

Answer:

good day philipines

Explanation:

aliya0001 [1]3 years ago
4 0

Answer:

hello

Explanation:

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(100 points) Atleast 5 slogans on saving fuel.
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Save Fuel, Save Earth

Fuel and time wait for none!

Be wise, don’t waste fuel

Save fuel, stop being cruel

Don’t contribute towards global warming

Care for future, save fuel

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3 years ago
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[HCN]=0.09974 M<br> Kp=7.52<br> Calculate the partial pressure of HCN ?
kvv77 [185]

Answer:

i don't understand

Explanation:

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3 years ago
A special danger of drug is that you
Whitepunk [10]
You get addicted and also you can get cancer please do not do drugs
4 0
3 years ago
A hot 123.3 g lump of an unknown substance initially at 164.2 °C is placed in 35.0 mL of water initially at 25.0 °C and the syst
Anuta_ua [19.1K]

Answer:

The unknown substance is rhodium.

Explanation:

Heat lost by hot substance will be equal to heat gained by the water

-Q_1=Q_2

Mass of substance= m_1=123.3 g

Specific heat capacity of substance= c_1=?

Initial temperature of the substance = T_1=164.2^oC

Final temperature of substance= T_2=T=48.6^oC

Q_1=m_1c_1\times (T-T_1)

Mass of water = M

Volume of water ,V= 35 ml

Density of water = d = 1.00 g/mL

M=d\times V=1.00 g/ml\times 35 mL=35 g

Mass of water= M = m_2=35 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=25.0^oC

Final temperature of water = T_3=T=48.6^oC

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

we get, c_1 =0.242 J/g^oC

The value of heat capacity of the substance is equal to that of rhodium metal.Hence, the unknown substance is rhodium.

4 0
3 years ago
13.3 g of benzene (C6H6) is dissolved in 282 g of carbon tetrachloride. What is the molal concentration of benzene in this solut
Verizon [17]

Answer:

0.605 molal

Explanation:

molality is the amount of solute in a particular mass of solvent.

lets calculate the amount of benzene solute.

mass of benzene= 13.3g

molar mass of C6H6= 12*6 +1*6 =72+7=78g/mol

amount of benzene= mass/molar mass

                           =13.3/78

                          =0.1705mol

molality= amount of solute/mass of solvent in kg

mass of solvent=282g=0.282kg

molality = 0.1705/0.282

    =0.605 molal

6 0
3 years ago
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