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Bess [88]
3 years ago
9

Which statement best describes the weather shown by the purple combination of semicircles and triangles on a line on a weather m

ap?
A warm front brings drizzly weather.

An occluded front can cause light to heavy precipitation that may last several days.

A cold front can cause heavy rain, thunder, and lightning.

A stationary front may produce rainy or snowy weather for several days.
Chemistry
2 answers:
BigorU [14]3 years ago
7 0

Answer:

D

Explanation:

Meteorologists use this symbol to show that the front is a stationary front.

Lunna [17]3 years ago
4 0
This is the answer I’m probably too late

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Does the surface area of an object affect how fast it falls?
ValentinkaMS [17]
No it do not but it uses gravity and falls fast So. The surface do not affect how fast objects fall. Hope this helps:)
7 0
3 years ago
Read 2 more answers
Calculate the molarity of 3.00 moles of KCL dissolved in 2.00L of solution.
skad [1K]

Answer:

 1.5 Molar solution in KCl

Explanation:

Definition of molarity => moles of solute / Volume of solution in Liters

Given 3.00 moles of solute dissolved in 2Liters of solution

Molarity of [KCl] = 3.00 moles KCl / 2Liters solution = 1.5 Molar solution in KCl

8 0
3 years ago
A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if
BigorU [14]
<h2>Hello!</h2>

The answer is: -97.23° C

<h2>Why?</h2>

Applying the Charles and Gay-Lussac's Law we have that:

\frac{V}{T}=k

Where:

<em>k </em>is the proportionality constant

<em>v</em> is the volume of the gas

<em>t</em> is the temperature of the gas

We also have the following relation:

\frac{V1}{T1}=\frac{V2}{T2}

Since we need to know the new temperature (T2) we can find it using the last equation, so:

\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K

We are asked to find the temperature in Celsius degrees, we must convert the result:

Celsius=K-273.15=175.92-273.15=-97.23

Therefore, the temperature is -97.23° C

Have a nice day!

6 0
4 years ago
How many grams of dextrose are needed to make 725 mL of a 26.0% (w/v) dextrose solution? Note that mass is not technically the s
Diano4ka-milaya [45]

Answer:

188.5g of dextrose are needed

Explanation:

In Weight per volume percentage - %(w/v) -, the concentration is defined as the mass of solute in grams -In this case, dextrose-, in 100mL of solution.

As you want to prepare 725mL of a 26.0% (w/v) solution. you need:

725mL * (26g / 100mL) = 188.5g of solute =

<h3>188.5g of dextrose are needed</h3>
3 0
3 years ago
List two SI-derived units for volume, and explain how they relate to the cubic centimeter.
Pavel [41]
Gases use Cubic Feet (cu.ft).
28,317 cc (cm³ or mL).

For liquids we have the US Gallon (gal).
1.0 US gal. = 3,785 cc (cm³ or mL).
3 0
3 years ago
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