Im having trouble figuring out the missing length and solving this, can I have some help?

When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2 – 3y ?

JulsSmile [24]

$3\cdot3^2-2\cdot5-(2\cdot3^2-3\cdot5)=27-10-(18-15)=17-3=14$

7 0

3 years ago

A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome

MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

7 0

2 years ago

A random sample of 38 wheel chair users were asked whether they preferred cushion type A or B, and 28 of them preferred type A w

-BARSIC- [3]

Answer:

The statement that cushion A is twice as popular as cushion B cannot be verified

Step-by-step explanation:

From the question we are told that:

Sample size n=38

Type a size A $X_a=28$

Type a size B $X_b=10$

Generally the probability of choosing cushion A P(a) is mathematically given by

$P(a)=\frac{28}{38}$

$P(a)=0.73$

Generally the equation for A to be twice as popular as B is mathematically given by

$P(b)+2P(b)=3P$

Therefore Hypothesis

$Null H_0: p \leq \frac{2P}{3P} \\Altenative H_A:p>\frac{2P}{3P}$

Generally the equation normal approx of p value is mathematically given by

$z=\frac{x-np_0-0.5}{\sqrt{np_0(1-p_0)} }$

$z=\frac{28-(38*2/3)_0-0.5}{\sqrt{38*2/3*1/3} }$

$z=0.75$

Therefore from distribution table

$Pvalue=1-\theta (0.75)$

$Pvalue=0.227$

Therefore there is no sufficient evidence to disagree with the Null hypothesis $H_0$

Therefore the statement that cushion A is twice as popular as cushion B cannot be verified

7 0

3 years ago

I need to know how to answer number 10

Ipatiy [6.2K]

Check the picture below.

3 0

3 years ago

The function f(x) is the total amount spent at a store, when purchasing x items that are $5 each and the items are not taxable

Keith_Richards [23]

F(x)=5x

normal domain: all real numbers
practical domain: <span>all positive integers

</span>becasue we can substituent with any positive integer in the place of x

3 0

3 years ago

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