Slope = (10-1)/(1+2) = 9/3 = 3
y = mx + b
1 = 3(-2) +b
1 = -6 + b
b = 7
equation
y = 3x + 7
or
3x - y = -7
answer is <span>3x − y = −7 (first choice)</span>
Answer:
the answer is 8
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given
z = 119 + 120 i
Let 
Squaring both sides

Comparing real and imaginary part
Re(LHS)=Re(RHS)
...........................(1)
comparing Im(LHS)=Im(RHS)
120=2pq

Substitute q in 1


Let 



we take only Positive value because 
x=149.85

thus 

thus,

Answer:
10: m=2/3ns
12: g=h-f/5
Step-by-step explanation:
Step-by-step explanation:
Close. You correctly set up the integrals. When integrating e²ˣ:
∫ e²ˣ dx
½ ∫ 2 e²ˣ dx
½ e²ˣ + C
So the coefficient should be ½, not 2.
[eˣ − ½ e²ˣ]₋₁⁰ + [½ e²ˣ − eˣ]₀¹
[(e⁰ − ½ e⁰) − (e⁻¹ − ½ e⁻²)] + [(½ e² − e) − (½ e⁰ − e⁰)]
1 − ½ − e⁻¹ + ½ e⁻² + ½ e² − e − ½ + 1
-e⁻¹ + ½ e⁻² + ½ e² − e + 1