All categories

2 years ago

WORTH 40 POINTS [−3−4x≤21]

Mathematics

1 answer:

Ierofanga [76]2 years ago

7 0

$\\ \tt\longmapsto -3-4x\leqslant 21$

$\\ \tt\longmapsto -4x\leqslant 21+3$

$\\ \tt\longmapsto -4x\leqslant 24$

$\\ \tt\longmapsto x\leqslant -6$

Option A

You might be interested in

What is the measure of arc BC?

Artist 52 [7]

9514 1404 393

Answer:

100°

Step-by-step explanation:

Arc BC is twice the measure of inscribed angle BEC, so is ...

arc BC = 2×50°

arc BC = 100°

5 0

2 years ago

Read 2 more answers

Which equation has a graph that goes through the points (4, -6) and (0, 6)?

Ugo [173]

Answer:

$y = -3x + 6\\$

Step-by-step explanation:

Find the gradient of the equation

$\frac{Difference in y}{Difference in x} \\\\\frac{6 - - 6}{0 - 4} = \frac{12}{-4} = -3$

The equation will have the gradient -3x

Use the general equation of a line, and substitute the coordinates in to find the y-intercept.

$y = x + c\\ y = -3x + c\\$

(4, -6)

$-6 = -3(4) + c\\ -6 = -12 + c\\ -6 + 12 = c\\ c = 6$ $6 = -3(0) + c\\ 6 = 0 + c\\ c = 6$

(0, 6)

$6 = -3(0) + c\\ 6 = -0 + c\\ c = 6$

The equation of the line is

$y = -3x + 6\\$

4 0

3 years ago

10+10= hhihihhhiihihihih

svetoff [14.1K]

Answer:

10+10=1010

Step-by-step explanation:

brainliest?

4 0

2 years ago

Read 2 more answers

Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p

Ymorist [56]

Answer:

$E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours$

$Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2$

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

$A\sim Uniform(1 ,7)$

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

$B\sim Exp(\lambda=\frac{1}{30 min})$

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

$E(A +B)$

Since the two random variables are assumed independent, then we have this

$E(A+B) = E(A)+E(B)$

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(A)=\frac{1+7}{2}=4 hours$

The expected value for the exponential distirbution is given by :

$E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx$

If we use the substitution $y=\lambda x$ we have this:

$E(X)=\frac{1}{\lambda} \int_{0}^\infty y e^{-\lambda y} dy =\frac{1}{\lambda}$

Where X represent the random variable and $\lambda$ the parameter. If we apply this formula to our case we got:

$E(B) =\frac{1}{\lambda}=\frac{1}{\frac{1}{30}}=30min$

We can convert this into hours and we got E(B) =0.5 hours, and then we can find:

$E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours$

And in order to find the variance for the random variable A+B we can find the individual variances:

$Var(A)= \frac{(b-a)^2}{12}=\frac{(7-1)^2}{12}=3 hours^2$

$Var(B) =\frac{1}{\lambda^2}=\frac{1}{(\frac{1}{30})^2}=900 min^2 x\frac{1hr^2}{3600 min^2}=0.25 hours^2$

We have the following property:

$Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)$

Since we have independnet variable the Cov(A,B)=0, so then:

$Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2$

3 0

3 years ago

Tash 3 write the Following in expanded form then in word form. 1. 355,645

Karolina [17]

Answer:

u will get a option like this when u put ur question then u can add photos!!

5 0

3 years ago

Read 2 more answers

***WORTH 40 POINTS*** [−3−4x≤21]

WORTH 40 POINTS [−3−4x≤21]