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alexira [117]
2 years ago
15

***WORTH 40 POINTS*** [−3−4x≤21]

Mathematics
1 answer:
Ierofanga [76]2 years ago
7 0

\\ \tt\longmapsto -3-4x\leqslant 21

\\ \tt\longmapsto -4x\leqslant 21+3

\\ \tt\longmapsto -4x\leqslant 24

\\ \tt\longmapsto x\leqslant -6

  • Option A
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Answer:

the plane's current height above the ocean is 3.42 miles

Step-by-step explanation:

Given that the diagonal distance between the plane and the aircraft carrier is 10 miles.

What we need to find is the vertical distance between the plane and the aircraft carrier which is the plane's current height above the ocean. This can be gotten using sine rule.  

For sine rule, you need a side and its opposite angle. For this question the triangle formed is a right angle triangle with diagonal distance, vertical distance and horizontal distance.

let a = diagonal distance = 10 miles

let the opposite angle to the diagonal distance be A = 90° (right angle)

let the vertical distance = b

let the opposite angle to the vertical distance be B = 20°

Sine rule states that    \frac{a}{sin(A)}  =  \frac{b}{sin(B)}

∴   \frac{10}{sin(90)}  =  \frac{b}{sin(20)}

b  =  sin(20)\frac{10}{sin(90)}

b  =  0.342*\frac{10}{1}

⇒ b = 3.42 miles

Therefore the plane's current height above the ocean is 3.42 miles

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3 years ago
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