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1 year ago

2x+4y=60 and y=x+3 i need a answer quick

Mathematics

1 answer:

Kay [80]1 year ago

7 0

It is asking for the intercept.

y = x + 3 becomes y - x = 3

multiply it by two, so it becomes -2x + 2y = 6. Then add it to the other equation, and solve for y.

2x + 4y = 60

(2x + 4y) + (-2x + 2y) = 60 +6

6y = 66

y = 11

Plug in the known y into the the easiest equation.

11 = x +3

x = 8

Intercept: (8, 11)

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Answer:

x = $\frac{3}{20}$

Step-by-step explanation:

Given

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Multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions

10x + 15 + 10(x - 1) = 8

10x + 15 + 10x - 10 = 8

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20x = 3 ( divide both sides by 20 )

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Step-by-step explanation:

Step(i):-

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

Step(ii):-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

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= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

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= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Final answer:-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

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We have the representation of this problem in the figure below. As we have a 10.3 mile race, then the equation is fulfilled as:

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