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2 years ago

Given the functions f(x)=1x−4+3 and g(x)=1x+1+6.

Mathematics

1 answer:

Lubov Fominskaja [6]2 years ago

8 0

The statement that describes the transformation of the graph of function f onto the graph of function g is:

The graph shifts 5 units left and 3 units up.

<h2>Transformations</h2>

The given functions are:

f(x) = (x-4) + 3

g(x) = (x+1) + 6

Comparing the functions f(x) = (x-4) + 3 and g(x) = (x+1) + 6

Difference between f(x) and g(x) on the x-axis = 1 - (-4) = 5

Difference between f(x) and g(x) on the y-axis = 6 - 3 = 3

From the comparison made above, we can conclude that:

The graph of f(x) is shifted to the left by 5 units to form g(x)

The graph of f(x) is shifted up by 3 units to form g(x

Learn more on transformation here: brainly.com/question/10222182

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I need to know what equals y

inn [45]

Since a^2 - b^2 = 1, the value of y = 1 because x=1 and 1^2 - 1^2 = 0

5 0

3 years ago

An automobile owner found that 20 years ago, 72% of Americans said that they would prefer to purchase an American automobile. He

LenaWriter [7]

Answer:

$z=\frac{0.884 -0.72}{\sqrt{\frac{0.72(1-0.72)}{43}}}=2.395$

Now we can find the p value taking incount that we are using a bilateral test

$p_v =2*P(z>2.395)=0.01662$

Since the p value is lower than the significance level of 0.1 we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of Americans that they would prefer an American automobile is significantly different from 0.72 and then the claim is correct

Step-by-step explanation:

Information given

n=43 represent the random sample taken

X=38 represent the Americans who they would prefer an American automobile

$\hat p=\frac{38}{43}=0.884$ estimated proportion of Americans that they would prefer an American automobile

$p_o=0.72$ is the value that we want to check

$\alpha=0.1$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the percentage of Americans that they would prefer an American automobile today differs from 72%, then the system of hypothesis are:

Null hypothesis: $p=0.72$

Alternative hypothesis: $p \neq 0.72$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.884 -0.72}{\sqrt{\frac{0.72(1-0.72)}{43}}}=2.395$

Now we can find the p value taking incount that we are using a bilateral test

$p_v =2*P(z>2.395)=0.01662$

5 0

3 years ago

If you wanted to make a game where you pay $5 if you can't guess a random dogs weight within 16lbs what payout should you offer

ella [17]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

The population std. dev of the dog weight=8

$\sigma=8\\\\P(\text{guess with in 16 lbs}) = P(|X-\mu|\leq 16)\\\\=P(-2 \leq Z \leq 2) = 0.9544\\\\$

Calculating the payout w s.t:

$E[netpay]=0=(-5) \times 0.9544+w\times (1-0.9544)\\\\ w =(5 \times \frac{0.9544}{1-0.9544}) =\$ 104.65$

therefore, we assume that the weight of the dog is a normal distribution with std. deviation that is 8.

4 0

3 years ago

((s+4)/(s^2+13s+36))*((s+9)/(9))

defon

$\bf \cfrac{s+4}{s^2+13s+36}\cdot \cfrac{s+9}{9}\implies \cfrac{\underline{s+4}}{\underline{(s+9)}\underline{(s+4)}}\cdot \cfrac{\underline{s+9}}{9}\implies \cfrac{1}{9}$

8 0

3 years ago

Simplify 2 to the 5th over 3 squared all raised to the 4th power.

son4ous [18]

I think that would be C but idk tell me if im right

8 0

3 years ago