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NemiM [27]
2 years ago
15

GIVING 50 POINTS Find the missing length indicated. Pls show your work

Mathematics
2 answers:
jasenka [17]2 years ago
8 0

\\ \sf\longmapsto \dfrac{x}{20}=\dfrac{6}{15}

\\ \sf\longmapsto 15x=120

\\ \sf\longmapsto x=\dfrac{120}{15}

\\ \sf\longmapsto x=8

aleksandrvk [35]2 years ago
7 0

Answer:

let the missing length =x

Then,by similiarty of triangle

\frac{6}{15}  =  \frac{x}{20}

<h2>X = 8 mark me as brainliest ❤️</h2>
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Answer:

Step-by-step explanation:

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If there is an option for (5x+8i)(5x-8i) this would be the answer

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ABCD is a rhombus. Find AB. Give answer as a fraction in simplest form.<br>​
LuckyWell [14K]

Answer:

The length of AB = 97/3 units

Step-by-step explanation:

  • The length of CD = 7x+2
  • The length of BC = 4x+15

We know that a rhombus is a quadrilateral whose four sides all have the same length.

Thus, the equation becomes

7x+2 = 4x+15

7x-4x = 15-2

3x = 13

x = 13/3

So, the length of CD = 7x+2 = 7(13/3)+2

                                               = 91/3 + 2

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And, the length of BC = 4x+15 = 4(13/3) + 15

                                                  = 97/3

  • We already know that a rhombus is a quadrilateral whose four sides all have the same length.

Thus, the length of AB = 97/3 units

         

5 0
3 years ago
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(f- g)(x) = x - 3

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This means that you have to subtract the two equation.

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f(x) - g(x) = [3x - 2] - [2x+1]

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2 years ago
Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

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Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

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So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

Hence, the equation of the polynomial is x^{3}-2 x^{2}-x+2=0

3 0
2 years ago
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