Answer and explanation:
They are not equivalent because if we simplify the second expression, the result isn't the same:
7(y×b)+3b
= 7(yb)+3b
=7yb + 3b
Therefore 7yb+3b≠7y+7b+3y
And even though you meant
7(y+b)+3b
=7y+7b+3b
=7y+10b
7y+10b≠10y+7b
15/17. The value (ratio) of cos A is 15/17.
The trigonometric ratios of an acute angle are, basically, the sine, the cosine and the tangent. They are defined from an acute angle, α, of a right triangle, whose elements are the hypotenuse, the leg contiguous to the angle, and the leg opposite the angle.
-The sine of the angle is the opposite leg divided by the hypotenuse.
-The cosine of the angle is the adjacent leg divided by the hypotenuse.
-The tangent of the angle is the opposite leg divided by the adjacent leg or, which is the same, the sine of the angle divided by the cosine of the angle.
cos A = adjacent leg/hypothenuse = BC/AC = 15/17
48,000
600/.10
*8 years would be 48,000
10:4 15:6 20:6 if those aren’t on there I ain’t ur guy
