Answer:
x = 2 sqrt(3)/3
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp / hyp
sin 60 = 1 /x
x sin 60 =1
x = 1 /sin 60
x = 1 / sqrt(3)/2
x = 2 sqrt(3)/3
Answer:
![\sqrt[4]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D)
Step-by-step explanation:
This was right on my test. I completely guessed so I don't really have an explanation.
What can a denominator never be?
0
so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.
so, what x values make our denominator 0?
to figure this out, we need to set (x-1)(x-2)=0
now we split and solve.

so when x is 1 or 2 the function doesnt make sense.
but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2
Answer:
- 
Step-by-step explanation:
Given
-
← divide numerator/ denominator by 14 )
= - 
The word is CALCULATE. ( to determine or ascertain by mathematical methods; compute