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Shkiper50 [21]
3 years ago
12

I keep getting stuck in this minus questions so help me please

Mathematics
1 answer:
allsm [11]3 years ago
5 0

Answer:

1 and 2/3 or 5/3

Step-by-step explanation:

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A system of equations is shown:
Harrizon [31]

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<h2>(1, 4)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}2x=-y+6&(1)\\-4x+3y=8&(2)\end{array}\right\\\\(1)\\-y+6=2x\qquad\text{subtract 6 from both sides}\\-y=2x-6\qquad\text{change the signs}\\y=6-2x\\\\\text{substitute it to (2):}\\\\(2)\\-4x+3(6-2x)=8\qquad\text{use the distributive property}\\-4x+(3)(6)+(3)(-2x)=8\\-4x+18-6x=8\qquad\text{subtract 18 from both sides}\\-10x=-10\qquad\text{divide both sides by (-10)}\\x=1\\\\\text{put the value of x to (1):}\\\\y=6-2(1)\\y=6-2\\y=4

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3 years ago
ASAP WILL GIVE BRAINLIEST
wlad13 [49]

Answer:

802.75 pi

Step-by-step explanation:

4 0
3 years ago
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Find the probability of choosing a penny or a dime from 4 pennies 3 nickeles and 6 dimes
bezimeni [28]

Answer:

5.0/5

Step-by-step explanation:

4 0
3 years ago
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A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are
Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that p = 0.75, and four games means that n = 4

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164

0.3164 = 31.64% probability the team wins all its conference games

4 0
3 years ago
X<br> ſocm<br> Jicm<br> A) 2V5 cm<br> B) V13 cm<br> D) V19 cm<br> C) 1 cm<br> ASAP
bulgar [2K]

Answer:

using pythagoras theorem

hyp 2=opp 2+adj 2

=( √6)(√6)+(√7)(√7)

hyp 2=13

hyp=√13

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3 years ago
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