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2 years ago

What is the relaxed form of dna in a cells nucleus?

Biology

2 answers:

coldgirl [10]2 years ago

6 0

Answer:

The relaxed form of DNA that can be found in the nucleus is referred to as chromatin. This form of DNA is observed when the cell is not dividing.

Explanation:

hope this helps

stich3 [128]2 years ago

3 0

The relaxed form of DNA in a cell's nucleus is called chromatin.

<h3>CHROMATIN:</h3>

Chromatin is a complex of DNA and histone proteins within the cell's nucleus. The DNA is too long to fit into the cell's nucleus, hence, is coiled around proteins called histones.

This complex forms the structure called chromatin, which then condenses during the prophase stage of cell division to form a more compact structure called chromosome.

Therefore, it can be said that the relaxed or uncondensed form of DNA in the nucleus of a cell is called chromatin.

Learn more about chromatin at: brainly.com/question/7228363

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9th grade biology question. 10pts

insens350 [35]

Answer:

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3 years ago

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Korvikt [17]

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3 years ago

A molecule that is phosphorylated

Stolb23 [73]

Has an increased chemical reactivity;it is primed to do cellular work should be your answer have a very nice day <span />

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3 years ago

Humerus bones from the same species of animal have approximately the same length-to-width ratios. It is known that Species A has

Dima020 [189]

Answer:

The unearthed Humerous bones don't belong to the species A.

Explanation:

Hello!

You are studying the Humerus bones species A, who is known to have a mean ratio of 8,5. This value corresponds to the population mean of the length-to-with ratio of bones of species A, symbolized as μ.

The hypothesis you want to study is "The Humorous bones unearthed belong to the species A" if you assume this to be true, then the mean of the length-to-with ratio should be equal to the known population mean of the length-to-with ratio.

Symbolized:

H₀: μ = 8,5

H₁: μ ≠ 8,5

Significance level: α: 0,05

You are asked to use a Z-test, since you don't know the value of the population variance, but have the sample values, the sample size is big enough (more than n=30). Assuming that the sample values are independent, the statistic test of choice is the approximation:

$Z= \frac{x_bar-μ}{S\sqrt[]{n} }$ ≅N(0;1)

The critical region, in this case, it's a two-tailed test (remember the type is determined by the null hypothesis) so you'll have two critical values.

Left value [/tex] $Z_{\alpha/2} = Z_{0,025} = -1,96$

Right value $Z_{1-\alpha/2} = Z_{0,975} = 1,96So you'll reject the null hyphotesis if the calculated [tex]Z_{obs}$ value is ≤-1,96 or ≥1,96 and you'll support it if -1,96< $Z_{obs}$ <1,96

Now we calculate the statistic by replacing the formula with the data:

x_bar = 9,26

S = 1,20

n = 41

$Z_{obs}= \frac{x_bar-μ}{S\sqrt[]{n} }$

$Z_{obs}= \frac{9,26-8,5}{1,20\sqrt[]{41} }$

$Z_{obs}$ = 4,0553

Since the calculated value falls in the rejection region, this means, you have statistically significant results. In other words you can reject the null hipothesis (H₀: μ = 8,5) and asume that the unearthed Humerous bones don't belong to the species A.

I hope you have a SUPER day!

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Sonja [21]

Answer:

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Explanation:

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4 years ago