2 years ago

A light bulb can be at most 50 watts to be safely used in this light fixture

1 answer:

8 0

Somewhat true but I need more information to this problem

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Ne4ueva [31]

Let:

$k\cdot IW=I^{\prime}W^{\prime}$

Where:

k = scale factor

IW = 12

I'W'= 8

so, solving for k:

$\begin{gathered} k=\frac{I^{\prime}W^{\prime}}{IW} \\ k=\frac{8}{12}=\frac{2}{3} \end{gathered}$

3 0

1 year ago

IceJOKER [234]

69% can be written as
69/100
That cannot be reduced any further since 69 and 100 do not have any common factors other than 1

4 0

3 years ago

olga_2 [115]

Answer:

2.6 and 5.4 are both the same sign, he should add them and then take that negative sign from (-5.4), so the answer would be -8.0.

5 0

3 years ago

tresset_1 [31]

Wooo nada I just want ya to be a good friend to

7 0

3 years ago

babymother [125]

Answer:

24/13 or 1.8

Step-by-step explanation:

27b -3 - 14b -21 = 0

13b - 24 = 0

13b = 24

b = 24/13 or 1.8

5 0

2 years ago