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Schach [20]
3 years ago
14

4. A surveying team needs to measure the distance across the lake. They make the measurements shown along the ground. What is th

e distance across the lake?
If necessary, round your answer to the nearest tenth.
Mathematics
1 answer:
Nataliya [291]3 years ago
8 0

Applying the Law of Cosines, the distance across the lake is: 2.1 miles.

<h3>What is the Law of Cosines?</h3>

Law of Cosines is given as:  c² = a² + b² - 2(a)(b)cos(C).

The diagram showing the measurements along the ground is in the attachment below.

Given:

  • a = 2.82 miles
  • b = 3.11 miles
  • C = 40.3°
  • c = distance across the lake.

Applying the Law of Cosines, we have:

c² = 2.82² + 3.11² - 2(2.82)(3.11)cos(40.3)

c² = 4.25

c = √4.25

c = 2.1 miles

Thus, applying the Law of Cosines, the distance across the lake is: 2.1 miles.

Learn more about Law of Cosines on:

brainly.com/question/4372174

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The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in
oksano4ka [1.4K]

Answer:

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

p_v =P(Z>2)=0.0228  

Step-by-step explanation:

1) Data given and notation  

\bar X=8300 represent the sample mean  

\sigma=1200 represent the population standard deviation  

n=64 sample size  

\mu_o =800 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :  

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

4) P-value  

Since is a one-side upper test the p value would given by:  

p_v =P(Z>2)=0.0228  

5) Conclusion  

If we compare the p value and the significance level assumed, for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.  

4 0
3 years ago
If a 10 symbol sequence is sent through the channel,what is the probability that up to 3 symbols are in error out of the 10trans
lina2011 [118]

Answer: 0.171887

Step-by-step explanation:

Given that S0 and S1 are binary symbol of equal probabilty;

P(S0) = P(S1) = 0.5

This probability is a Binomial random variable of sequence Sn, where Sn counting the number of success in a repeated trials.

P(Sn =X) = nCx p^x (1-p)^(n-1)

Pr(at most 3) = P(0<= x <=3) = P(X=0) + 0) + P(X=1) + P(X=2) + P(X=3)

Since there are only 2 values that occur in sequence 0 and 1 ( or S0 and S1).Let the distribution be given by the sequence (0111111111),(1011111111),(11011111111),...(1111111110) for Sn= 1 is the sequence for 1 error.

10C0, 10C1, 10C2, and 10C3 is the number of sequences in value for X= 0, 1, 2, 3 having value 0 and others are 1. Let the success be p(S0)=0.5 and p(S1)= 0.5

P(0<= X <=3) = 10C0 × (0.5)^0 × (0.5)^10 + 10C1× (0.5)¹ × (0.5)^9 + 10C2 × (0.5)² × (0.5)^8 + 10C3(0.5)³(0.5)^7

= 1 × (0.5)^10 + 10 × (0.5)^10 + 45 × (0.5)^10 + 120 × (0.5)^10

=0.000977 + 0.00977 + 0.04395 + 0.11719

= 0.171887

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tino4ka555 [31]
(0,3)

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