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kirza4 [7]
2 years ago
9

Which line has a slope of -1/2? Line a Line b Line c Line d

Mathematics
2 answers:
photoshop1234 [79]2 years ago
5 0

Answer:

line D i think

Step-by-step explanation:

line a and c have a positive slope. and line b has a way negative slope.

Alex787 [66]2 years ago
4 0

Answer:

Line D

Step-by-step explanation:

In a slope, the numerator is the rise, and the denominator is the run. So, if the slope is -1/2, the line will go down 1 unit, and right 2 units.

-hope it helps

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Evaluate <br> f(x)=5x-3<br> f(5) =
Kaylis [27]

f(x)=5x-3

use the substitution method

f(5)=(5)(5)-3

multiply the parentheses first

using: PEDMAS

P=Parentheses

E= Exponents

D=Division

M=Multiplication

A= Addition

S=Subtraction

(5)(5)=25

25-3

=22

answer:

f(5)=22

5 0
3 years ago
Which of the equations below shows the relationship in the table?
kogti [31]

Answer:

Im Sure its A

Step-by-step explanation:

3 0
3 years ago
Vesna vulovic survived the longest fall on record without a parachute when her plane exploded and she fell 6 miles and 551 yards
Alenkinab [10]
316.80 feet, this is from a conversion on google, may not be 100% accurate.
6 0
2 years ago
Read 2 more answers
Help anyone plezzzzzzzzzzzzzzzzzzz
emmainna [20.7K]
              <span> Direct-substituting x = -2 gives 0/0, so we know that by the factor theorem, both the numerator and denominator have a factor of x + 2. From there, we can cancel out the conflicting factors and apply the limit.

We can factor the numerator and denominator to get:

x^3 - x^2 - x + 10 = (x + 2)(x^2 - 3x + 5)
x^2 + 3x + 2 = (x + 2)(x + 1).

So we have:

lim (x-->-2) (x^3 - x^2 - x + 10)/(x^2 + 3x + 2)
= lim (x-->-2) [(x + 2)(x^2 - 3x + 5)]/[(x + 2)(x + 1)]
= lim (x-->-2) (x^2 - 3x + 5)/(x + 1), by canceling out x + 2
= [2^2 - 3(-2) + 5]/(-2 + 1)
= (4 + 6 + 5)/(-1)
= -15.

I hope this helps! </span>
7 0
3 years ago
Jarvis began operations on January 1, Year 1 with an owner investment of $12,400. There have been no additional owner investment
anygoal [31]

(a)  The statement of owner's equity for Year 1  is $26,920

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(a) Preparation of  the statement of owner's equity for Year 1 at its December 31 year end.

JARVIS statement of owner's equity for year ended December 31 Year 1  

Owner investment  $12,400

Add Net income $ 33,600

Less Jarvis, Withdrawals ($ 19,080)

Statement of owner's equity for Year 1 $26,920

(b) Preparation of  the statement of owner's equity for Year 2 at its December 31 year end.

JARVIS statement of owner's equity for year ended December 31 Year 2

Owner investment $12,400

Add Net income  $ 56,000

Less  Jarvis, Withdrawals  $ 15,680

Statement of owner's equity for Year 2 $52,720

Learn more here:.

brainly.com/question/17062268

6 0
3 years ago
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